Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι → ι → ο be given.
Assume H0:
∀ x4 . x4 ∈ x0 ⟶ x3 (ap x1 x4) (ap x2 x4).
Assume H1: ∀ x4 . x3 x4 x4.
Assume H2:
∀ x4 x5 . 3897e.. x0 x1 x2 x4 x5 ⟶ x3 x4 x5 ⟶ x3 x5 x4.
Assume H3:
∀ x4 x5 x6 . 3897e.. x0 x1 x2 x4 x5 ⟶ x3 x4 x5 ⟶ 3897e.. x0 x1 x2 x5 x6 ⟶ x3 x5 x6 ⟶ x3 x4 x6.
Claim L4:
∀ x4 x5 . 3897e.. x0 x1 x2 x4 x5 ⟶ and (3897e.. x0 x1 x2 x4 x5) (x3 x4 x5)
Let x4 of type ι be given.
Let x5 of type ι be given.
Apply H4 with
λ x6 x7 . and (3897e.. x0 x1 x2 x6 x7) (x3 x6 x7) leaving 4 subgoals.
Let x6 of type ι be given.
Assume H5: x6 ∈ x0.
Apply andI with
3897e.. x0 x1 x2 (ap x1 x6) (ap x2 x6),
x3 (ap x1 x6) (ap x2 x6) leaving 2 subgoals.
Apply unknownprop_4a9ee00be3059282c1c2c04c263a8ef11d5d96bde5e2cce739d1bcaa19845c62 with
x0,
x1,
x2,
x6.
The subproof is completed by applying H5.
Apply H0 with
x6.
The subproof is completed by applying H5.
Let x6 of type ι be given.
Apply andI with
3897e.. x0 x1 x2 x6 x6,
x3 x6 x6 leaving 2 subgoals.
The subproof is completed by applying unknownprop_f30a9971af522a7c6d48fce7503318aee70245a8fb07686f8a91c05461df8720 with x0, x1, x2, x6.
The subproof is completed by applying H1 with x6.
Let x6 of type ι be given.
Let x7 of type ι be given.
Assume H5:
and (3897e.. x0 x1 x2 x6 x7) (x3 x6 x7).
Apply H5 with
and (3897e.. x0 x1 x2 x7 x6) (x3 x7 x6).
Assume H7: x3 x6 x7.
Apply andI with
3897e.. x0 x1 x2 x7 x6,
x3 x7 x6 leaving 2 subgoals.
Apply unknownprop_6fd31505fe5649eb2fd16580ea5d6e63ee118f3692b3972694e2469c77d587b4 with
x0,
x1,
x2,
x6,
x7.
The subproof is completed by applying H6.
Apply H2 with
x6,
x7 leaving 2 subgoals.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Assume H5:
and (3897e.. x0 x1 x2 x6 x7) (x3 x6 x7).
Assume H6:
and (3897e.. x0 x1 x2 x7 x8) (x3 x7 x8).
Apply H5 with
and (3897e.. x0 x1 x2 x6 x8) (x3 x6 x8).
Assume H8: x3 x6 x7.
Let x4 of type ι be given.
Let x5 of type ι be given.
Apply L4 with
x4,
x5,
x3 x4 x5 leaving 2 subgoals.
The subproof is completed by applying H5.
Assume H7: x3 x4 x5.
The subproof is completed by applying H7.