Let x0 of type ι → ι → ο be given.
Let x1 of type ι → ι be given.
Assume H0:
∀ x2 . x2 ∈ u12 ⟶ x1 x2 ∈ u12.
Assume H1:
∀ x2 . x2 ∈ u12 ⟶ ∀ x3 . x3 ∈ u12 ⟶ x1 x2 = x1 x3 ⟶ x2 = x3.
Assume H2:
∀ x2 . x2 ∈ u12 ⟶ ∀ x3 . x3 ∈ u12 ⟶ x0 (x1 x2) (x1 x3) ⟶ x0 x2 x3.
Let x2 of type ι be given.
Assume H9:
∀ x3 . x3 ∈ x2 ⟶ ∀ x4 . x4 ∈ x2 ⟶ not (x0 x3 x4).
Let x3 of type ο be given.
Assume H11:
∀ x4 . x4 ⊆ u12 ⟶ atleastp u5 x4 ⟶ (∀ x5 . x5 ∈ x4 ⟶ ∀ x6 . x6 ∈ x4 ⟶ not (x0 x5 x6)) ⟶ u8 ∈ x4 ⟶ u9 ∈ x4 ⟶ x3.
Assume H12:
∀ x4 . x4 ⊆ u12 ⟶ atleastp u5 x4 ⟶ (∀ x5 . x5 ∈ x4 ⟶ ∀ x6 . x6 ∈ x4 ⟶ not (x0 x5 x6)) ⟶ u8 ∈ x4 ⟶ u10 ∈ x4 ⟶ x3.
Assume H13:
∀ x4 . x4 ⊆ u12 ⟶ atleastp u5 x4 ⟶ (∀ x5 . x5 ∈ x4 ⟶ ∀ x6 . x6 ∈ x4 ⟶ not (x0 x5 x6)) ⟶ u9 ∈ x4 ⟶ u10 ∈ x4 ⟶ x3.
Apply unknownprop_8d334858d1804afd99b1b9082715c7f916daee31e697b66b5c752e0c8756ebae with
setminus x2 u8,
x3 leaving 2 subgoals.
The subproof is completed by applying H10.
Apply L15 with
x3.
Let x4 of type ι be given.
Let x5 of type ι be given.
Assume H24: x4 ∈ x5.
Apply setminusE with
x2,
u8,
x4,
x3 leaving 2 subgoals.
The subproof is completed by applying H22.
Assume H25: x4 ∈ x2.
Apply setminusE with
x2,
u8,
x5,
x3 leaving 2 subgoals.
The subproof is completed by applying H23.
Assume H27: x5 ∈ x2.
Apply L14 with
x4,
x3 leaving 6 subgoals.
Apply H7 with
x4.
The subproof is completed by applying H25.
Apply FalseE with
x3.
Apply H26.
The subproof is completed by applying H29.
Apply L14 with
x5,
x3 leaving 6 subgoals.
Apply H7 with
x5.
The subproof is completed by applying H27.
Apply FalseE with
x3.
Apply H28.
The subproof is completed by applying H30.
Apply FalseE with
x3.
Apply In_irref with
x4.
Apply H29 with
λ x6 x7 . x4 ∈ x7.
Apply H30 with
λ x6 x7 . x4 ∈ x6.
The subproof is completed by applying H24.
Apply H11 with
x2 leaving 5 subgoals.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
Apply H29 with
λ x6 x7 . x6 ∈ x2.
The subproof is completed by applying H25.
Apply H30 with
λ x6 x7 . x6 ∈ x2.
The subproof is completed by applying H27.
Apply H12 with
x2 leaving 5 subgoals.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
Apply H29 with
λ x6 x7 . x6 ∈ x2.
The subproof is completed by applying H25.
Apply H30 with
λ x6 x7 . x6 ∈ x2.
The subproof is completed by applying H27.