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Proofgold Proof

pf
Let x0 of type ο be given.
Let x1 of type ο be given.
Assume H0: x1 ⟶ not x0.
Assume H1: not x1 ⟶ x0.
Apply xm with x1, exactly1of2 x0 x1 leaving 2 subgoals.
Assume H2: x1.
Apply exactly1of2_I2 with x0, x1 leaving 2 subgoals.
Apply H0.
The subproof is completed by applying H2.
The subproof is completed by applying H2.
Assume H2: not x1.
Apply exactly1of2_I1 with x0, x1 leaving 2 subgoals.
Apply H1.
The subproof is completed by applying H2.
The subproof is completed by applying H2.
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