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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Apply unknownprop_b456609235d152f08bccfce314d541d7c44f3716137c00b0ce21cf467ba83d17 with 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))))))), λ x9 . If_i (x9 = 4a7ef..) x0 (If_i (x9 = 4ae4a.. 4a7ef..) x1 (If_i (x9 = 4ae4a.. (4ae4a.. 4a7ef..)) x2 (If_i (x9 = 4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))) x3 (If_i (x9 = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) x4 (If_i (x9 = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))))) x5 (If_i (x9 = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))))) x6 (If_i (x9 = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))))))) x7 x8))))))), 4a7ef.., λ x9 x10 . x10 = x0 leaving 2 subgoals.
The subproof is completed by applying unknownprop_e664fa2efc433515bf02717582533e586f06e7031b9cda60cb27b9cb8817c10b.
Apply If_i_1 with 4a7ef.. = 4a7ef.., x0, If_i (4a7ef.. = 4ae4a.. 4a7ef..) x1 (If_i (4a7ef.. = 4ae4a.. (4ae4a.. 4a7ef..)) x2 (If_i (4a7ef.. = 4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))) x3 (If_i (4a7ef.. = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) x4 (If_i (4a7ef.. = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))))) x5 (If_i (4a7ef.. = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))))) x6 (If_i (4a7ef.. = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))))))) x7 x8)))))).
Let x9 of type ιιο be given.
Assume H0: x9 4a7ef.. 4a7ef...
The subproof is completed by applying H0.