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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type (ιι) → ο be given.
Assume H0: ∀ x2 : ι → ι . x1 x2∀ x3 . x0 x3x0 (x2 x3).
Assume H1: ∀ x2 x3 : ι → ι . x1 x2x1 x3∀ x4 . x0 x4x2 (x3 x4) = x3 (x2 x4).
Let x2 of type ιι be given.
Let x3 of type ιι be given.
Let x4 of type ιι be given.
Let x5 of type ιι be given.
Let x6 of type ιι be given.
Let x7 of type ιι be given.
Let x8 of type ιι be given.
Let x9 of type ιι be given.
Assume H2: x1 x2.
Assume H3: x1 x3.
Assume H4: x1 x4.
Assume H5: x1 x5.
Assume H6: x1 x6.
Assume H7: x1 x7.
Assume H8: x1 x8.
Assume H9: x1 x9.
Let x10 of type ι be given.
Assume H10: x0 x10.
Apply H1 with x2, x3, x4 (x5 (x6 (x7 (x8 (x9 x10))))) leaving 3 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
Apply unknownprop_9df0051fe5649d34dd14e90f9946f82bcfe3445ae6c6fefd9c7d30607b4a3534 with x0, x1, x9, x8, x7, x6, x5, x4, x10 leaving 8 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H9.
The subproof is completed by applying H8.
The subproof is completed by applying H7.
The subproof is completed by applying H6.
The subproof is completed by applying H5.
The subproof is completed by applying H4.
The subproof is completed by applying H10.