Apply unknownprop_a84c26fe1e8eab090e46587a2dce33d43adea76dac76ef9e457538086747ff10 with
λ x0 . f4dc0.. (f4dc0.. x0) = x0.
Let x0 of type ι be given.
Let x1 of type ι be given.
Apply H0 with
f4dc0.. (f4dc0.. (02a50.. x0 x1)) = 02a50.. x0 x1.
Apply H3 with
(∀ x2 . prim1 x2 x0 ⟶ ∀ x3 . prim1 x3 x1 ⟶ 099f3.. x2 x3) ⟶ f4dc0.. (f4dc0.. (02a50.. x0 x1)) = 02a50.. x0 x1.
Apply unknownprop_34fa0f857eadb854ca355983a4ae0231c847f4ec451cfc0522270cf37c3c2aff with
x0,
x1,
f4dc0.. (f4dc0.. (02a50.. x0 x1)) leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying L9.
Let x2 of type ι be given.
Apply H1 with
x2,
λ x3 x4 . 099f3.. x3 (f4dc0.. (f4dc0.. (02a50.. x0 x1))) leaving 2 subgoals.
The subproof is completed by applying H10.
Apply H4 with
x2.
The subproof is completed by applying H10.
Apply unknownprop_8fbd0c2b48e78882e15936a0ad5f4a3c5af2cb37d9320d8cb210a91462e202ca with
x2.
The subproof is completed by applying L11.
Apply unknownprop_3cc82c9758d3882690e6647e4154486613d1a5c615c0651627364410273ab026 with
f4dc0.. (02a50.. x0 x1),
f4dc0.. x2 leaving 3 subgoals.
The subproof is completed by applying L8.
The subproof is completed by applying L12.
Apply unknownprop_3cc82c9758d3882690e6647e4154486613d1a5c615c0651627364410273ab026 with
x2,
02a50.. x0 x1 leaving 3 subgoals.
The subproof is completed by applying L11.
The subproof is completed by applying L7.
Apply unknownprop_9d3d7e3a3303096ebb406ebd4ae6c5aff572ffe215624d21fe33216d8b0e1bc7 with
x0,
x1,
x2 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H10.
Let x2 of type ι be given.
Apply H2 with
x2,
λ x3 x4 . ... leaving 2 subgoals.
Apply L10 with
f4dc0.. (f4dc0.. (02a50.. x0 x1)) = 02a50.. x0 x1.
Let x2 of type ι → ι → ο be given.
Apply unknownprop_c3102c186c7aa1001a5c1b1b7ecab6b25bcd639e713104221ece8bf414726a69 with
02a50.. x0 x1,
f4dc0.. (f4dc0.. (02a50.. x0 x1)),
λ x3 x4 . x2 x4 x3 leaving 4 subgoals.
The subproof is completed by applying L7.
The subproof is completed by applying L9.
The subproof is completed by applying H12.