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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Assume H0: radical_field_extension x0 x1.
Let x2 of type ο be given.
Assume H1: Field x0Field x1subfield x0 x1∀ x3 . x3omega∀ x4 . ap x4 0 = x0ap x4 x3 = x1(∀ x5 . x5ordsucc x3Field (ap x4 x5))(∀ x5 . x5ordsucc x3∀ x6 . x6ordsucc x5subfield (ap x4 x6) (ap x4 x5))(∀ x5 . x5x3∃ x6 . and (x6field0 (ap x4 (ordsucc x5))) (∃ x7 . and (x7omega) (and (CRing_with_id_omega_exp (ap x4 (ordsucc x5)) x6 x7field0 (ap x4 x5)) (Field_extension_by_1 (ap x4 x5) (ap x4 (ordsucc x5)) x6))))x2.
Apply H0 with x2.
Let x3 of type ι be given.
Assume H2: (λ x4 . and (x4omega) (∃ x5 . and (and (and (ap x5 0 = x0) (ap x5 x4 = x1)) (∀ x6 . x6ordsucc x4Field (ap x5 x6))) (∀ x6 . x6x4∃ x7 . and (x7field0 (ap x5 (ordsucc x6))) (∃ x8 . and (x8omega) (and (CRing_with_id_omega_exp (ap x5 (ordsucc x6)) x7 x8field0 (ap x5 x6)) (Field_extension_by_1 (ap x5 x6) (ap x5 (ordsucc x6)) x7)))))) x3.
Apply H2 with x2.
Assume H3: x3omega.
Assume H4: ∃ x4 . and (and (and (ap x4 0 = x0) (ap x4 x3 = x1)) (∀ x5 . x5ordsucc x3Field (ap x4 x5))) (∀ x5 . x5x3∃ x6 . and (x6field0 (ap x4 (ordsucc x5))) (∃ x7 . and (x7omega) (and (CRing_with_id_omega_exp (ap x4 (ordsucc x5)) x6 x7field0 (ap x4 x5)) (Field_extension_by_1 (ap x4 x5) (ap x4 (ordsucc x5)) x6)))).
Apply H4 with x2.
Let x4 of type ι be given.
Assume H5: (λ x5 . and (and (and (ap x5 0 = x0) (ap x5 x3 = x1)) (∀ x6 . x6ordsucc x3Field (ap x5 x6))) (∀ x6 . ...∃ x7 . and (x7field0 (ap x5 ...)) ...)) ....
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