Let x0 of type ι → ι → ο be given.
Let x1 of type ι → ι → ο be given.
Let x2 of type ι → ι → ο be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι → ι be given.
Let x9 of type ι → ι be given.
Let x10 of type ι → ι → ι be given.
Let x11 of type ι → ι → ι be given.
Let x12 of type ι → ι → ι be given.
Let x13 of type ι → ο be given.
Let x14 of type ι → ο be given.
Let x15 of type ι → ο be given.
Let x16 of type ι → ο be given.
Let x17 of type ι → ο be given.
Let x18 of type ι → ο be given.
Let x19 of type ι → ο be given.
Let x20 of type ι → ο be given.
Let x21 of type ι → ο be given.
Let x22 of type ι → ο be given.
Let x23 of type ι → ο be given.
Assume H0: x0 x3 x4.
Assume H1: x0 x3 x5.
Assume H2: ∀ x24 x25 . x1 x25 x24 ⟶ x0 x25 (x8 x24).
Assume H3: ∀ x24 . x1 x24 x24.
Assume H4: ∀ x24 x25 x26 . x1 (x10 (x10 x24 x25) x26) (x10 x24 (x10 x25 x26)).
Assume H5: ∀ x24 x25 . x2 (x12 x24 x25) (x11 x24 x25).
Assume H6:
∀ x24 x25 . not (x0 x25 (x9 x24)) ⟶ not (x25 = x24).
Assume H7: ∀ x24 x25 . x0 x25 x24 ⟶ x16 x24 ⟶ x15 (x12 x24 (x9 x25)).
Assume H8: ∀ x24 x25 . x0 x25 x24 ⟶ x15 (x12 x24 (x9 x25)) ⟶ x16 x24.
Assume H9: ∀ x24 x25 . x2 x24 x25 ⟶ x19 x24 ⟶ x19 x25 ⟶ x21 (x10 x24 x25).
Assume H10: ∀ x24 x25 . x22 x24 ⟶ x19 (x11 x24 x25) ⟶ x20 (x12 x24 x25).
Assume H11:
not (x1 x6 x5).
Assume H12:
not (x5 = x6).
Assume H13: x0 x4 (x9 x4).
Assume H14: x0 (x9 x4) (x12 (x8 x5) x5).
Assume H15: x1 x4 (x12 x6 (x9 x4)).
Assume H16: x0 x5 (x12 (x8 x5) x5).
Assume H17:
not (x1 (x9 x4) (x9 (x9 x4))).
Assume H18:
not (x3 = x10 (x9 x4) (x9 (x9 x4))).
Assume H19: x1 (x9 (x9 x4)) (x12 (x8 x5) (x9 x5)).
Assume H20:
not (x5 = x8 (x9 x4)).
Assume H21:
∀ x24 . x1 x24 (x8 (x9 x4)) ⟶ x0 (x9 x4) x24 ⟶ or (or (or (x24 = x3) (x24 = x4)) (x24 = x9 (x9 x4))) (x24 = x8 (x9 x4)).
Assume H22:
not (x5 = x8 x5).
Assume H23:
not (x5 = x9 x5).
Assume H24:
not (x6 = x8 x5).
Assume H25: x0 x3 (x12 (x8 (x10 (x9 x4) (x9 (x9 x4)))) (x9 (x10 (x9 x4) (x9 (x9 x4))))).
Assume H26:
not (x0 x6 (x8 (x9 x5))).
Assume H27: x0 x5 (x10 x6 (x9 (x9 x5))).
Assume H28: ....