Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type (ι → ο) → ο be given.
Let x3 of type (ι → ο) → ο be given.
Let x4 of type ι → ι → ι be given.
Let x5 of type ι → ι → ι be given.
Apply unknownprop_1e110a2b0eac66e464fcd0049e51159c6573a7f238676ed96b2b7556f087fb8f with
e0718.. x0 x2 x4,
x1,
x3,
x5.
The subproof is completed by applying H0.
Claim L2: x0 = x1
Apply L1 with
λ x6 x7 . x0 = x7.
The subproof is completed by applying unknownprop_c7497c326e0bcb75fa2cc505e6dafed2f342db0b83093fa52226d04b865b9a91 with x0, x2, x4.
Apply and3I with
x0 = x1,
∀ x6 : ι → ο . (∀ x7 . x6 x7 ⟶ prim1 x7 x0) ⟶ x2 x6 = x3 x6,
∀ x6 . prim1 x6 x0 ⟶ ∀ x7 . prim1 x7 x0 ⟶ x4 x6 x7 = x5 x6 x7 leaving 3 subgoals.
The subproof is completed by applying L2.
Let x6 of type ι → ο be given.
Assume H3:
∀ x7 . x6 x7 ⟶ prim1 x7 x0.
Apply unknownprop_71d4b3d2b3a5f29d2cd05a29c47b2f0fa1a64aff8b5bd681eeb78733ed987d9d with
x0,
x2,
x4,
x6,
λ x7 x8 : ο . x8 = x3 x6 leaving 2 subgoals.
The subproof is completed by applying H3.
Claim L4:
∀ x7 . x6 x7 ⟶ prim1 x7 x1
Apply L2 with
λ x7 x8 . ∀ x9 . x6 x9 ⟶ prim1 x9 x7.
The subproof is completed by applying H3.
Apply H0 with
λ x7 x8 . decode_c (f482f.. x8 (4ae4a.. 4a7ef..)) x6 = x3 x6.
Let x7 of type ο → ο → ο be given.
Apply unknownprop_71d4b3d2b3a5f29d2cd05a29c47b2f0fa1a64aff8b5bd681eeb78733ed987d9d with
x1,
x3,
x5,
x6,
λ x8 x9 : ο . x7 x9 x8.
The subproof is completed by applying L4.
Let x6 of type ι be given.
Let x7 of type ι be given.
Apply unknownprop_b1715816bd75ab55604fa7666530ab99e6bf52403540cf592ed4c4fda9cb0db1 with
x0,
x2,
x4,
x6,
x7,
λ x8 x9 . x9 = x5 x6 x7 leaving 3 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
Apply L2 with
λ x8 x9 . prim1 x6 x8.
The subproof is completed by applying H3.
Apply L2 with
λ x8 x9 . prim1 x7 x8.
The subproof is completed by applying H4.
Apply H0 with
λ x8 x9 . e3162.. (f482f.. x9 (4ae4a.. (4ae4a.. 4a7ef..))) x6 x7 = x5 x6 x7.
Let x8 of type ι → ι → ο be given.
Apply unknownprop_b1715816bd75ab55604fa7666530ab99e6bf52403540cf592ed4c4fda9cb0db1 with
x1,
x3,
x5,
x6,
x7,
λ x9 x10 . x8 x10 x9 leaving 2 subgoals.
The subproof is completed by applying L5.
The subproof is completed by applying L6.