Let x0 of type ι → ι → ο be given.
Let x1 of type ι → ι → ο be given.
Let x2 of type ι → ι → ο be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι → ι be given.
Let x9 of type ι → ι be given.
Let x10 of type ι → ι → ι be given.
Let x11 of type ι → ι → ι be given.
Let x12 of type ι → ι → ι be given.
Let x13 of type ι → ο be given.
Let x14 of type ι → ο be given.
Let x15 of type ι → ο be given.
Let x16 of type ι → ο be given.
Let x17 of type ι → ο be given.
Let x18 of type ι → ο be given.
Let x19 of type ι → ο be given.
Let x20 of type ι → ο be given.
Let x21 of type ι → ο be given.
Let x22 of type ι → ο be given.
Let x23 of type ι → ο be given.
Assume H0:
∀ x24 . iff (x13 x24) (∃ x25 . and (x0 x25 x24) (not (x1 x24 (x8 x25)))).
Assume H1:
∀ x24 . iff (x17 x24) (∃ x25 . and (x1 x25 x24) (and (not (x1 x24 x25)) (x16 x25))).
Assume H2:
∀ x24 . not (x0 x24 x24).
Assume H3: ∀ x24 x25 x26 . x1 x26 x25 ⟶ x1 (x12 x24 x25) (x12 x24 x26).
Assume H4: ∀ x24 x25 . x0 x24 x25 ⟶ x13 (x8 x25).
Assume H5:
∀ x24 x25 . x0 x25 x24 ⟶ not (x18 x24) ⟶ not (x17 (x12 x24 (x9 x25))).
Assume H6: ∀ x24 x25 . x1 x24 x25 ⟶ x14 x24 ⟶ x14 x25.
Assume H7:
∀ x24 x25 . not (x17 x24) ⟶ x13 (x11 x24 x25) ⟶ not (x15 (x12 x24 x25)).
Assume H8: ∀ x24 x25 . x0 x25 x24 ⟶ x16 x24 ⟶ x15 (x12 x24 (x9 x25)).
Assume H9: ∀ x24 x25 . x0 x25 x24 ⟶ x14 (x12 x24 (x9 x25)) ⟶ x15 x24.
Assume H10: ∀ x24 x25 . x2 x24 x25 ⟶ x19 x24 ⟶ x19 x25 ⟶ x21 (x10 x24 x25).
Assume H11:
not (x0 x3 x3).
Assume H12:
not (x3 = x12 (x8 x5) x5).
Assume H13: x0 (x9 x4) (x10 (x9 x4) (x9 (x9 x4))).
Assume H14:
not (x1 x5 (x9 x5)).
Assume H15:
not (x1 (x9 x4) (x9 x5)).
Assume H16:
not (x1 (x9 x4) (x9 (x9 x4))).
Assume H17:
not (x0 (x9 x4) x6).
Assume H18:
not (x0 (x9 x4) (x12 (x8 x5) (x8 (x9 x4)))).
Assume H19:
∀ x24 . x1 x24 (x8 (x9 x4)) ⟶ not (x0 (x9 x4) x24) ⟶ not (x0 x3 x24) ⟶ or (or (or (x24 = x3) (x24 = x4)) (x24 = x9 (x9 x4))) (x24 = x8 (x9 x4)).
Assume H20:
not (x0 (x12 (x8 x5) (x8 (x9 x5))) (x12 (x8 x5) (x9 x5))).
Assume H21:
not (x0 (x9 (x9 x4)) x6).
Assume H22:
not (x3 = ...).