Let x0 of type ο be given.
Let x1 of type ο be given.
Apply unknownprop_205dfda454738bda674e818ce60f3fddbf0921edb32095af6ffb25f2a0bd5888 with
λ x2 x3 : ο → ο → ο . x3 x0 x1 ⟶ ∀ x4 : ο . (x0 ⟶ not x1 ⟶ x4) ⟶ (not x0 ⟶ x1 ⟶ x4) ⟶ x4.
Assume H0:
(λ x2 x3 : ο . or (and x2 (not x3)) (and (not x2) x3)) x0 x1.
Let x2 of type ο be given.
Assume H1:
x0 ⟶ not x1 ⟶ x2.
Assume H2:
not x0 ⟶ x1 ⟶ x2.
Apply unknownprop_eb8e8f72a91f1b934993d4cb19c84c8270f73a3626f3022b683d960a7fef89cb with
and x0 (not x1),
and (not x0) x1,
x2 leaving 3 subgoals.
The subproof is completed by applying H0.
Apply andE with
x0,
not x1,
x2 leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H1.
Apply andE with
not x0,
x1,
x2 leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H2.