Let x0 of type ι → ι → ο be given.
Let x1 of type ι → ι → ο be given.
Let x2 of type ι → ι → ο be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι → ι be given.
Let x9 of type ι → ι be given.
Let x10 of type ι → ι → ι be given.
Let x11 of type ι → ι → ι be given.
Let x12 of type ι → ι → ι be given.
Let x13 of type ι → ο be given.
Let x14 of type ι → ο be given.
Let x15 of type ι → ο be given.
Let x16 of type ι → ο be given.
Let x17 of type ι → ο be given.
Let x18 of type ι → ο be given.
Let x19 of type ι → ο be given.
Let x20 of type ι → ο be given.
Let x21 of type ι → ο be given.
Let x22 of type ι → ο be given.
Let x23 of type ι → ο be given.
Assume H0:
∀ x24 . iff (x13 x24) (∃ x25 . and (x0 x25 x24) (not (x1 x24 (x8 x25)))).
Assume H1:
∀ x24 . iff (x0 x24 x6) (or (or (x24 = x3) (x24 = x4)) (x24 = x5)).
Assume H2:
∀ x24 x25 x26 . iff (x0 x26 (x11 x24 x25)) (and (x0 x26 x24) (x0 x26 x25)).
Assume H3: ∀ x24 x25 x26 . x0 x26 x25 ⟶ x0 x26 (x10 x24 x25).
Assume H4: ∀ x24 x25 x26 . x1 (x10 x24 (x10 x25 x26)) (x10 (x10 x24 x25) x26).
Assume H5: ∀ x24 x25 x26 . x1 x26 x25 ⟶ x1 (x12 x24 x25) (x12 x24 x26).
Assume H6:
∀ x24 x25 x26 . (∀ x27 . x0 x27 x24 ⟶ not (x0 x27 x25) ⟶ x0 x27 x26) ⟶ x1 (x12 x24 x25) x26.
Assume H7:
∀ x24 x25 . (∀ x26 . x0 x26 x24 ⟶ not (x0 x26 x25)) ⟶ x2 x24 x25.
Assume H8:
∀ x24 x25 x26 . not (x0 x26 x24) ⟶ not (x0 x26 (x12 x24 x25)).
Assume H9:
∀ x24 x25 x26 . x0 x25 x24 ⟶ x0 x26 x24 ⟶ not (x25 = x26) ⟶ x13 x24.
Assume H10:
∀ x24 x25 . not (x24 = x25) ⟶ x13 (x10 (x9 x24) (x9 x25)).
Assume H11: ∀ x24 x25 . x1 x24 x25 ⟶ x14 x24 ⟶ x14 x25.
Assume H12: ∀ x24 x25 . x0 x25 x24 ⟶ x14 x24 ⟶ x13 (x12 x24 (x9 x25)).
Assume H13:
not (x4 = x5).
Assume H14: ∀ x24 . x0 x24 (x9 x4) ⟶ x24 = x4.
Assume H15:
not (x4 = x9 x4).
Assume H16:
not (x0 (x9 x4) x5).
Assume H17: x0 x4 (x12 (x8 x5) (x9 x5)).
Assume H18:
not (x0 (x9 x5) x4).
Assume H19:
not (x0 x3 (x9 (x9 x4))).
Assume H20: x0 (x9 x4) (x10 (x9 x4) (x9 (x9 x4))).
Assume H21: x1 x4 (x12 x6 (x9 x4)).
Assume H22:
not (x1 x5 (x12 x6 (x9 x4))).
Assume H23:
∀ x24 . ... ⟶ or (or (or (x24 = x3) (x24 = x4)) (... = ...)) ....