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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Assume H0: SNo x0.
Assume H1: SNo x1.
Assume H2: SNo x2.
Assume H3: SNo x3.
Assume H4: SNo x4.
Assume H5: SNo x5.
Apply minus_add_SNo_distr_m_4 with x0, x1, x2, x3, add_SNo (minus_SNo x4) x5, λ x6 x7 . x7 = add_SNo x0 (add_SNo x1 (add_SNo x2 (add_SNo x3 (add_SNo x4 (minus_SNo x5))))) leaving 6 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
Apply SNo_add_SNo with minus_SNo x4, x5 leaving 2 subgoals.
Apply SNo_minus_SNo with x4.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
Apply minus_add_SNo_distr_m with x4, x5, λ x6 x7 . add_SNo x0 (add_SNo x1 (add_SNo x2 (add_SNo x3 x7))) = add_SNo x0 (add_SNo x1 (add_SNo x2 (add_SNo x3 (add_SNo x4 (minus_SNo x5))))) leaving 3 subgoals.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
Let x6 of type ιιο be given.
Assume H6: x6 (add_SNo x0 (add_SNo x1 (add_SNo x2 (add_SNo x3 (add_SNo x4 (minus_SNo x5)))))) (add_SNo x0 (add_SNo x1 (add_SNo x2 (add_SNo x3 (add_SNo x4 (minus_SNo x5)))))).
The subproof is completed by applying H6.