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Proofgold Proof

pf
Let x0 of type ι be given.
Assume H0: ordinal x0.
Claim L1: SNo x0
Apply ordinal_SNo with x0.
The subproof is completed by applying H0.
Claim L2: SNoLev x0 = x0
Apply ordinal_SNoLev with x0.
The subproof is completed by applying H0.
Apply set_ext with SNoL x0, SNoS_ x0 leaving 2 subgoals.
Let x1 of type ι be given.
Assume H3: x1SNoL x0.
Apply SNoL_E with x0, x1, x1SNoS_ x0 leaving 3 subgoals.
The subproof is completed by applying L1.
The subproof is completed by applying H3.
Assume H4: SNo x1.
Assume H5: SNoLev x1SNoLev x0.
Assume H6: SNoLt x1 x0.
Apply L2 with λ x2 x3 . x1SNoS_ x2.
Apply SNoS_I2 with x1, x0 leaving 3 subgoals.
The subproof is completed by applying H4.
The subproof is completed by applying L1.
The subproof is completed by applying H5.
Let x1 of type ι be given.
Assume H3: x1SNoS_ x0.
Apply SNoS_E2 with x0, x1, x1SNoL x0 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H3.
Assume H4: SNoLev x1x0.
Assume H5: ordinal (SNoLev x1).
Assume H6: SNo x1.
Assume H7: SNo_ (SNoLev x1) x1.
Apply SNoL_I with x0, x1 leaving 4 subgoals.
The subproof is completed by applying L1.
The subproof is completed by applying H6.
Apply L2 with λ x2 x3 . SNoLev x1x3.
The subproof is completed by applying H4.
Apply ordinal_SNoLev_max with x0, x1 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H6.
The subproof is completed by applying H4.