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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type ιιιο be given.
Let x2 of type ιι be given.
Let x3 of type ιιιιιι be given.
Let x4 of type ιο be given.
Let x5 of type ιιιο be given.
Let x6 of type ιι be given.
Let x7 of type ιιιιιι be given.
Let x8 of type ιι be given.
Let x9 of type ιιιι be given.
The subproof is completed by applying and4E with ∀ x10 . x0 x10x4 (x8 x10), ∀ x10 x11 x12 . x0 x10x0 x11x1 x10 x11 x12x5 (x8 x10) (x8 x11) (x9 x10 x11 x12), ∀ x10 . x0 x10x9 x10 x10 (x2 x10) = x6 (x8 x10), ∀ x10 x11 x12 x13 x14 . x0 x10x0 x11x0 x12x1 x10 x11 x13x1 x11 x12 x14x9 x10 x12 (x3 x10 x11 x12 x14 x13) = x7 (x8 x10) (x8 x11) (x8 x12) (x9 x11 x12 x14) (x9 x10 x11 x13).