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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιι be given.
Assume H0: {x2 ∈ x0|∀ x3 . x3prim4 x0x1 x3x3x2x3}prim4 x0.
Assume H1: x1 {x2 ∈ x0|∀ x3 . x3prim4 x0x1 x3x3x2x3}prim4 x0.
Assume H2: ∀ x2 . x2prim4 x0x1 x2x2{x3 ∈ x0|∀ x4 . x4prim4 x0x1 x4x4x3x4}x2.
Assume H3: x1 {x2 ∈ x0|∀ x3 . x3prim4 x0x1 x3x3x2x3}{x2 ∈ x0|∀ x3 . x3prim4 x0x1 x3x3x2x3}.
Assume H4: x1 (x1 {x2 ∈ x0|∀ x3 . x3prim4 x0x1 x3x3x2x3})x1 {x2 ∈ x0|∀ x3 . x3prim4 x0x1 x3x3x2x3}.
Let x2 of type ο be given.
Assume H5: ∀ x3 . and (x3prim4 x0) (x1 x3 = x3)x2.
Apply H5 with {x3 ∈ x0|∀ x4 . x4prim4 x0x1 x4x4x3x4}.
Apply andI with {x3 ∈ x0|∀ x4 . x4prim4 x0x1 x4x4x3x4}prim4 x0, x1 {x3 ∈ x0|∀ x4 . x4prim4 x0x1 x4x4x3x4} = {x3 ∈ x0|∀ x4 . x4prim4 x0x1 x4x4x3x4} leaving 2 subgoals.
The subproof is completed by applying H0.
Apply set_ext with x1 {x3 ∈ x0|∀ x4 . x4prim4 x0x1 x4x4x3x4}, {x3 ∈ x0|∀ x4 . x4prim4 x0x1 x4x4x3x4} leaving 2 subgoals.
The subproof is completed by applying H3.
Apply H2 with x1 {x3 ∈ x0|∀ x4 . x4prim4 x0x1 x4x4x3x4} leaving 2 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H4.