Let x0 of type ι → ο be given.
Let x1 of type ι → ι → ι be given.
Let x2 of type ι → ι → ι be given.
Assume H0: ∀ x3 x4 . x0 x3 ⟶ x0 x4 ⟶ x0 (x1 x3 x4).
Assume H1: ∀ x3 x4 x5 . x0 x3 ⟶ x0 x4 ⟶ x0 x5 ⟶ x2 x3 (x1 x4 x5) = x1 (x2 x3 x4) (x2 x3 x5).
Assume H2: ∀ x3 x4 x5 . x0 x3 ⟶ x0 x4 ⟶ x0 x5 ⟶ x2 (x1 x3 x4) x5 = x1 (x2 x3 x5) (x2 x4 x5).
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Assume H3: x0 x3.
Assume H4: x0 x4.
Assume H5: x0 x5.
Assume H6: x0 x6.
Assume H7: x0 x7.
Assume H8: x0 x8.
Assume H9: x0 x9.
Apply H2 with
x3,
x4,
x1 x5 (x1 x6 (x1 x7 (x1 x8 x9))),
λ x10 x11 . x11 = x1 (x1 (x2 x3 x5) (x1 (x2 x3 x6) (x1 (x2 x3 x7) (x1 (x2 x3 x8) (x2 x3 x9))))) (x1 (x2 x4 x5) (x1 (x2 x4 x6) (x1 (x2 x4 x7) (x1 (x2 x4 x8) (x2 x4 x9))))) leaving 4 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
Apply unknownprop_d7ce6357a8261c6a4be44f579bedcb1c2d65cec14964ea078af8f02cc5aab85a with
x0,
x1,
x5,
x6,
x7,
x8,
x9 leaving 6 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
Apply unknownprop_ba42d8afab82952b0d7dfc0b0a5aca8e776863449ac4fa660349884f276c83d1 with
x0,
x1,
x2,
x5,
x6,
x7,
x8,
x9,
x3,
λ x10 x11 . x1 x11 (x2 x4 (x1 x5 (x1 x6 (x1 x7 (x1 x8 x9))))) = x1 (x1 (x2 x3 x5) (x1 (x2 x3 x6) (x1 (x2 x3 x7) (x1 (x2 x3 x8) (x2 x3 x9))))) (x1 (x2 x4 x5) (x1 (x2 x4 x6) (x1 (x2 x4 x7) (x1 (x2 x4 x8) (x2 x4 x9))))) leaving 9 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H3.
Apply unknownprop_ba42d8afab82952b0d7dfc0b0a5aca8e776863449ac4fa660349884f276c83d1 with
x0,
x1,
x2,
x5,
x6,
x7,
x8,
x9,
x4,
λ x10 x11 . x1 (x1 (x2 x3 x5) (x1 (x2 x3 x6) (x1 (x2 x3 x7) (x1 (x2 x3 x8) (x2 x3 x9))))) x11 = x1 (x1 (x2 x3 x5) (x1 (x2 x3 x6) (x1 (x2 x3 x7) (x1 (x2 x3 x8) (x2 x3 x9))))) (x1 (x2 x4 x5) (x1 (x2 x4 x6) (x1 (x2 ... ...) ...))) leaving 9 subgoals.