Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Let x10 of type ι be given.
Let x11 of type ι be given.
Let x12 of type ι be given.
Let x13 of type ι be given.
Let x14 of type ι be given.
Let x15 of type ι be given.
Let x16 of type ι be given.
Let x17 of type ι be given.
Let x18 of type ι be given.
Let x19 of type ι be given.
Let x20 of type ι be given.
Let x21 of type ι be given.
Let x22 of type ι be given.
Let x23 of type ι be given.
Let x24 of type ι be given.
Let x25 of type ι be given.
Let x26 of type ι be given.
Let x27 of type ι be given.
Let x28 of type ι be given.
Let x29 of type ι be given.
Let x30 of type ι be given.
Let x31 of type ι be given.
Let x32 of type ι be given.
Let x33 of type ι be given.
Let x34 of type ι be given.
Let x35 of type ι be given.
Let x36 of type ι be given.
Let x37 of type ι be given.
Let x38 of type ι be given.
Let x39 of type ι be given.
Apply unknownprop_029be7aac5b226c27c91b7a859bf257dcfc0cc55808ec8290a641ff59740483c with
x0,
x1,
x2,
x3,
x4,
x5,
x6,
x7,
x8,
x9,
x10,
x11,
x12,
x13,
x14,
x15,
x16,
x17,
x18,
x19,
x20,
x21,
x22,
x23,
x24,
x25,
x26,
x27,
x28,
x29,
x30,
x31,
x32,
x33,
x34,
x35,
x36,
x37,
add_SNo (minus_SNo x38) x39,
λ x40 x41 . x41 = add_SNo x0 (add_SNo x1 (add_SNo x2 (add_SNo x3 (add_SNo x4 (add_SNo x5 (add_SNo x6 (add_SNo x7 (add_SNo x8 (add_SNo x9 (add_SNo x10 (add_SNo x11 (add_SNo x12 (add_SNo x13 (add_SNo x14 (add_SNo x15 (add_SNo x16 (add_SNo x17 (add_SNo x18 (add_SNo x19 (add_SNo x20 (add_SNo x21 (add_SNo x22 (add_SNo x23 (add_SNo x24 (add_SNo x25 (add_SNo x26 (add_SNo x27 (add_SNo x28 (add_SNo x29 (add_SNo x30 (add_SNo x31 (add_SNo x32 (add_SNo x33 (add_SNo x34 (add_SNo x35 (add_SNo x36 (add_SNo x37 (add_SNo x38 (minus_SNo x39))))))))))))))))))))))))))))))))))))))) leaving 40 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
The subproof is completed by applying H11.
The subproof is completed by applying H12.
The subproof is completed by applying H13.
The subproof is completed by applying H14.
The subproof is completed by applying H15.
The subproof is completed by applying H16.
The subproof is completed by applying H17.
The subproof is completed by applying H18.
The subproof is completed by applying H19.
The subproof is completed by applying H20.
The subproof is completed by applying H21.
The subproof is completed by applying H22.
The subproof is completed by applying H23.
The subproof is completed by applying H24.
The subproof is completed by applying H25.
The subproof is completed by applying H26.
The subproof is completed by applying H27.
The subproof is completed by applying H28.
The subproof is completed by applying H29.
The subproof is completed by applying H30.
The subproof is completed by applying H31.
The subproof is completed by applying H32.
The subproof is completed by applying H33.
The subproof is completed by applying H34.
The subproof is completed by applying H35.
The subproof is completed by applying H36.
The subproof is completed by applying H37.
Apply SNo_add_SNo with
minus_SNo x38,
x39 leaving 2 subgoals.
Apply SNo_minus_SNo with
x38.
The subproof is completed by applying H38.
The subproof is completed by applying H39.
Apply minus_add_SNo_distr_m with
x38,
x39,
... leaving 3 subgoals.