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Proofgold Proof

pf
Claim L0: ...
...
Claim L1: ∀ x0 . ∀ x1 : ι → ι → ι . (∀ x2 . x2x0∀ x3 . x3x0x1 x2 x3x0)127dd.. x0 x1∀ x2 . ∀ x3 : ι → ι → ι . (∀ x4 . x4x2∀ x5 . x5x2x3 x4 x5x2)127dd.. x2 x3∀ x4 x5 . MagmaHom (pack_b x0 x1) (pack_b x2 x3) x4MagmaHom (pack_b x0 x1) (pack_b x2 x3) x5∀ x6 : ι → ι → ι . (∀ x7 . x7{x8 ∈ x0|ap x4 x8 = ap x5 x8}∀ x8 . x8{x9 ∈ x0|ap x4 x9 = ap x5 x9}x1 x7 x8 = x6 x7 x8)127dd.. {x7 ∈ x0|ap x4 x7 = ap x5 x7} x6
Let x0 of type ι be given.
Let x1 of type ιιι be given.
Assume H1: ∀ x2 . x2x0∀ x3 . x3x0x1 x2 x3x0.
Assume H2: 127dd.. x0 x1.
Let x2 of type ι be given.
Let x3 of type ιιι be given.
Assume H3: ∀ x4 . x4x2∀ x5 . x5x2x3 x4 x5x2.
Assume H4: 127dd.. x2 x3.
Let x4 of type ι be given.
Let x5 of type ι be given.
Assume H5: MagmaHom (pack_b x0 x1) (pack_b x2 x3) x4.
Assume H6: MagmaHom (pack_b x0 x1) (pack_b x2 x3) x5.
Let x6 of type ιιι be given.
Assume H7: ∀ x7 . x7{x8 ∈ x0|ap x4 x8 = ap x5 x8}∀ x8 . x8{x9 ∈ x0|ap x4 x9 = ap x5 x9}x1 x7 x8 = x6 x7 x8.
Apply H2 with 127dd.. {x7 ∈ x0|ap x4 x7 = ap x5 x7} x6.
Assume H8: explicit_Group x0 x1.
Assume H9: explicit_abelian x0 x1.
Apply H4 with 127dd.. {x7 ∈ x0|ap x4 x7 = ap x5 x7} x6.
Assume H10: explicit_Group x2 x3.
Assume H11: explicit_abelian x2 x3.
Apply andI with explicit_Group {x7 ∈ x0|ap x4 x7 = ap x5 x7} x6, explicit_abelian {x7 ∈ x0|ap x4 x7 = ap x5 x7} x6 leaving 2 subgoals.
Apply unknownprop_25b39f95acc38e90496ee4808ab1a128bdb11a29e9c4569e1287049e660c9b38 with x0, x1, x2, x3, x4, x5, x6 leaving 7 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H8.
The subproof is completed by applying H3.
The subproof is completed by applying H10.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
Let x7 of type ι be given.
Assume H12: x7{x8 ∈ x0|ap x4 x8 = ap x5 x8}.
Let x8 of type ι be given.
Assume H13: x8{x9 ∈ x0|ap x4 x9 = ap ... ...}.
...
Apply unknownprop_cffd5c2c6377c7c9139709f837f7b00ba99be51fbf6add4c20b3723106916eaa with 127dd.. leaving 2 subgoals.
The subproof is completed by applying L0.
The subproof is completed by applying L1.