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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Assume H0: x1x0.
Let x2 of type ιι be given.
Let x3 of type ιι be given.
Assume H1: ∀ x4 . x4x0x2 x4x0.
Let x4 of type ιι be given.
Assume H2: ∀ x5 . x5x0x4 (x2 x5) = x3 (x4 x5).
Apply nat_ind with λ x5 . x4 (1319b.. x5 x2 x1) = 1319b.. x5 x3 (x4 x1) leaving 2 subgoals.
Apply unknownprop_039fc83525f9619f7cfecb750766b6bca3d944a312bec3cbff47462eeab06c10 with x2, x1, λ x5 x6 . x4 x6 = 1319b.. 0 x3 (x4 x1).
Apply unknownprop_039fc83525f9619f7cfecb750766b6bca3d944a312bec3cbff47462eeab06c10 with x3, x4 x1, λ x5 x6 . x4 x1 = x6.
Let x5 of type ιιο be given.
Assume H3: x5 (x4 x1) (x4 x1).
The subproof is completed by applying H3.
Let x5 of type ι be given.
Assume H3: nat_p x5.
Assume H4: x4 (1319b.. x5 x2 x1) = 1319b.. x5 x3 (x4 x1).
Apply unknownprop_002dbea24d6e2c65c6cefd906b209766da62711ebb920e89995e5f3cbbd95f66 with x5, x2, x1, λ x6 x7 . x4 x7 = 1319b.. (ordsucc x5) x3 (x4 x1) leaving 2 subgoals.
Apply nat_p_omega with x5.
The subproof is completed by applying H3.
Apply unknownprop_002dbea24d6e2c65c6cefd906b209766da62711ebb920e89995e5f3cbbd95f66 with x5, x3, x4 x1, λ x6 x7 . x4 (x2 (1319b.. x5 x2 x1)) = x7 leaving 2 subgoals.
Apply nat_p_omega with x5.
The subproof is completed by applying H3.
Apply H2 with 1319b.. x5 x2 x1, λ x6 x7 . x7 = x3 (1319b.. x5 x3 (x4 x1)) leaving 2 subgoals.
Apply unknownprop_634dfe6db60252fae5fb11b99d8182640cd8d27dd5c6123b0e5c5ff1eb699c89 with x0, x1, x2, x5 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
set y6 to be x3 (x4 (1319b.. x5 x2 x1))
set y7 to be x4 (1319b.. y6 x4 (x5 x2))
Claim L5: ∀ x8 : ι → ο . x8 y7x8 y6
Let x8 of type ιο be given.
Assume H5: x8 (x5 (1319b.. y7 x5 (y6 x3))).
set y9 to be λ x9 . x8
Apply H4 with λ x10 x11 . y9 (x5 x10) (x5 x11).
The subproof is completed by applying H5.
Let x8 of type ιιο be given.
Apply L5 with λ x9 . x8 x9 y7x8 y7 x9.
Assume H6: x8 y7 y7.
The subproof is completed by applying H6.