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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιο be given.
Let x2 of type ιο be given.
Assume H0: ∀ x3 . In x3 x0x1 x3x2 x3.
Assume H1: ∀ x3 . In x3 x0not (x1 x3)x2 ((λ x4 . SetAdjoin x4 (Sing 1)) x3).
Let x3 of type ι be given.
Apply unknownprop_ced40c82bec9d84d6ad8baec4b6c3b8f494372339c236cd16f6538e936263b63 with λ x4 x5 : ι → (ι → ο) → ι . In x3 (x5 x0 x1)x2 x3.
Assume H2: In x3 (binunion (Sep x0 (λ x4 . x1 x4)) (ReplSep x0 (λ x4 . not (x1 x4)) (λ x4 . (λ x5 . SetAdjoin x5 (Sing 1)) x4))).
Apply unknownprop_a497a9c4fdb392b95b688b10c74f8f445a953a0c88030ccc02fa0b24e4758231 with Sep x0 (λ x4 . x1 x4), ReplSep x0 (λ x4 . not (x1 x4)) (λ x4 . (λ x5 . SetAdjoin x5 (Sing 1)) x4), x3, x2 x3 leaving 3 subgoals.
The subproof is completed by applying H2.
Assume H3: In x3 (Sep x0 (λ x4 . x1 x4)).
Apply unknownprop_6a6b356f855b99f3fbff4effcb62e3ee6aa23839e10650eb28a503a368c2bb09 with x0, x1, x3, x2 x3 leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H0 with x3.
Assume H3: In x3 (ReplSep x0 (λ x4 . not (x1 x4)) (λ x4 . (λ x5 . SetAdjoin x5 (Sing 1)) x4)).
Apply unknownprop_021a576837934491f6aaf936d4c5a9c68d45f2b77fcd13cc395cfdeec72f7dac with x0, λ x4 . not (x1 x4), λ x4 . (λ x5 . SetAdjoin x5 (Sing 1)) x4, x3, x2 x3 leaving 2 subgoals.
The subproof is completed by applying H3.
Let x4 of type ι be given.
Assume H4: In x4 x0.
Assume H5: not (x1 x4).
Assume H6: x3 = (λ x5 . SetAdjoin x5 (Sing 1)) x4.
Apply H6 with λ x5 x6 . x2 x6.
Apply H1 with x4 leaving 2 subgoals.
The subproof is completed by applying H4.
The subproof is completed by applying H5.