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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type (ιι) → ο be given.
Assume H0: ∀ x2 : ι → ι . x1 x2∀ x3 . x0 x3x0 (x2 x3).
Assume H1: ∀ x2 x3 : ι → ι . x1 x2x1 x3∀ x4 . x0 x4x2 (x3 x4) = x3 (x2 x4).
Let x2 of type ιι be given.
Let x3 of type ιι be given.
Let x4 of type ιι be given.
Let x5 of type ιι be given.
Assume H2: x1 x2.
Assume H3: x1 x3.
Assume H4: x1 x4.
Assume H5: x1 x5.
Let x6 of type ι be given.
Assume H6: x0 x6.
Apply H1 with x2, x3, x4 (x5 x6) leaving 3 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
Apply unknownprop_dd12bbe0d4a49d4392f0cf8bc87d132f205c2fd6bffb6ab963d1738be94e2fba with x0, x1, x5, x4, x6 leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H5.
The subproof is completed by applying H4.
The subproof is completed by applying H6.