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Proofgold Proof

pf
Apply add_nat_SR with u51, 12, λ x0 x1 . x1 = u64 leaving 2 subgoals.
The subproof is completed by applying nat_12.
Apply add_nat_SR with u51, 11, λ x0 x1 . ordsucc x1 = u64 leaving 2 subgoals.
The subproof is completed by applying nat_11.
Apply add_nat_SR with u51, 10, λ x0 x1 . ordsucc (ordsucc x1) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_10.
Apply add_nat_SR with u51, 9, λ x0 x1 . ordsucc (ordsucc (ordsucc x1)) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_9.
Apply add_nat_SR with u51, 8, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc x1))) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_8.
Apply add_nat_SR with u51, 7, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc (ordsucc x1)))) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_7.
Apply add_nat_SR with u51, 6, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc x1))))) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_6.
Apply add_nat_SR with u51, 5, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc x1)))))) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_5.
Apply add_nat_SR with u51, 4, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc x1))))))) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_4.
Apply add_nat_SR with u51, 3, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc x1)))))))) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_3.
Apply add_nat_SR with u51, 2, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc x1))))))))) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_2.
Apply add_nat_SR with u51, 1, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc x1)))))))))) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_1.
Apply add_nat_SR with u51, 0, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc x1))))))))))) = u64 leaving 2 subgoals.
The subproof is completed by applying nat_0.
Apply add_nat_0R with u51, λ x0 x1 . ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc (ordsucc x1)))))))))))) = u64.
Let x0 of type ιιο be given.
The subproof is completed by applying H0.