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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type ιιι be given.
Let x2 of type ιιι be given.
Assume H0: ∀ x3 x4 . x0 x3x0 x4x0 (x1 x3 x4).
Assume H1: ∀ x3 x4 x5 . x0 x3x0 x4x0 x5x2 x3 (x1 x4 x5) = x1 (x2 x3 x4) (x2 x3 x5).
Assume H2: ∀ x3 x4 x5 . x0 x3x0 x4x0 x5x2 (x1 x3 x4) x5 = x1 (x2 x3 x5) (x2 x4 x5).
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Let x10 of type ι be given.
Let x11 of type ι be given.
Let x12 of type ι be given.
Let x13 of type ι be given.
Assume H3: x0 x3.
Assume H4: x0 x4.
Assume H5: x0 x5.
Assume H6: x0 x6.
Assume H7: x0 x7.
Assume H8: x0 x8.
Assume H9: x0 x9.
Assume H10: x0 x10.
Assume H11: x0 x11.
Assume H12: x0 x12.
Assume H13: x0 x13.
Apply unknownprop_55de5c79fadd89ca3e161a61e8ef1cc68aeee5eba6c4fec4d11d6eacbce11bf5 with x0, x1, x2, x3, x4, x5, x6, x7, x1 x8 (x1 x9 (x1 x10 (x1 x11 (x1 x12 x13)))), λ x14 x15 . x15 = x1 (x1 (x2 x3 x8) (x1 (x2 x3 x9) (x1 (x2 x3 x10) (x1 (x2 x3 x11) (x1 (x2 x3 x12) (x2 x3 x13)))))) (x1 (x1 (x2 x4 x8) (x1 (x2 x4 x9) (x1 (x2 x4 x10) (x1 (x2 x4 x11) (x1 (x2 x4 x12) (x2 x4 x13)))))) (x1 (x1 (x2 x5 x8) (x1 (x2 x5 x9) (x1 (x2 x5 x10) (x1 (x2 x5 x11) (x1 (x2 x5 x12) (x2 x5 x13)))))) (x1 (x1 (x2 x6 x8) (x1 (x2 x6 x9) (x1 (x2 x6 x10) (x1 (x2 x6 x11) (x1 (x2 x6 x12) (x2 x6 x13)))))) (x1 (x2 x7 x8) (x1 (x2 x7 x9) (x1 (x2 x7 x10) (x1 (x2 x7 x11) (x1 (x2 x7 x12) (x2 x7 x13))))))))) leaving 9 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
Apply unknownprop_14619fcdadc5a43502995316176da02be54150d716fe5c9727e811d162c28b04 with x0, x1, x8, x9, x10, x11, x12, x13 leaving 7 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
The subproof is completed by applying H11.
The subproof is completed by applying H12.
The subproof is completed by applying H13.
Apply unknownprop_db57eabbae8f01f7ede64b544fc17e1b3344b7e5e868205273f289357efa3c25 with x0, x1, x2, x8, x9, x10, x11, x12, x13, x3, λ x14 x15 . x1 x15 (x1 (x2 x4 (x1 x8 (x1 x9 (x1 x10 (x1 ... ...))))) ...) = ... leaving 10 subgoals.
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