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Proofgold Proof
pf
Let x0 of type
ι
be given.
Assume H0:
SNo
x0
.
Assume H1:
SNoLt
0
x0
.
Apply recip_SNo_pos_prop1 with
x0
,
mul_SNo
x0
(
recip_SNo_pos
x0
)
=
1
leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Assume H2:
SNo
(
recip_SNo_pos
x0
)
.
Assume H3:
mul_SNo
x0
(
recip_SNo_pos
x0
)
=
1
.
The subproof is completed by applying H3.
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