Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Let x10 of type ι be given.
Let x11 of type ι be given.
Apply SNo_minus_SNo with
x6.
The subproof is completed by applying H6.
Apply SNo_minus_SNo with
x7.
The subproof is completed by applying H7.
Apply SNo_minus_SNo with
x8.
The subproof is completed by applying H8.
Apply SNo_minus_SNo with
x9.
The subproof is completed by applying H9.
Apply SNo_minus_SNo with
x10.
The subproof is completed by applying H10.
Apply SNo_minus_SNo with
x11.
The subproof is completed by applying H11.
Apply idl_negcycle_6 with
x0,
x1,
x2,
x3,
x4,
x5,
minus_SNo x6,
minus_SNo x7,
minus_SNo x8,
minus_SNo x9,
minus_SNo x10,
minus_SNo x11 leaving 19 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying L19.
The subproof is completed by applying L20.
The subproof is completed by applying L21.
The subproof is completed by applying L22.
The subproof is completed by applying L23.
The subproof is completed by applying L24.
Apply minus_SNo_Lt_contra3 with
0,
add_SNo (minus_SNo x6) (add_SNo (minus_SNo x7) (add_SNo (minus_SNo x8) (add_SNo (minus_SNo x9) (add_SNo (minus_SNo x10) (minus_SNo x11))))) leaving 3 subgoals.
The subproof is completed by applying SNo_0.
Apply SNo_add_SNo_6 with
minus_SNo x6,
minus_SNo x7,
minus_SNo x8,
minus_SNo x9,
minus_SNo x10,
minus_SNo x11 leaving 6 subgoals.
The subproof is completed by applying L19.
The subproof is completed by applying L20.
The subproof is completed by applying L21.
The subproof is completed by applying L22.
The subproof is completed by applying L23.
The subproof is completed by applying L24.
Apply minus_SNo_0 with
λ x12 x13 . SNoLt x13 (minus_SNo (add_SNo (minus_SNo x6) (add_SNo (minus_SNo x7) (add_SNo (minus_SNo x8) (add_SNo (minus_SNo x9) (add_SNo (minus_SNo x10) (minus_SNo x11))))))).
Apply minus_add_SNo_distr_m_5 with
x6,
x7,
x8,
x9,
x10,
minus_SNo x11,
λ x12 x13 . SNoLt 0 x13 leaving 7 subgoals.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
The subproof is completed by applying L24.
Apply minus_SNo_invol with
x11,
λ x12 x13 . SNoLt 0 (add_SNo x6 (add_SNo x7 (add_SNo x8 (add_SNo x9 (add_SNo x10 x13))))) leaving 2 subgoals.
The subproof is completed by applying H11.
The subproof is completed by applying H12.
Apply minus_SNo_Le_swap with
x6,
x0,
x1 leaving 4 subgoals.
The subproof is completed by applying H6.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H13.
Apply minus_SNo_Le_swap with
x7,
x1,
x2 leaving 4 subgoals.
The subproof is completed by applying H7.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H14.
Apply minus_SNo_Le_swap with
x8,
x2,
x3 leaving 4 subgoals.
The subproof is completed by applying H8.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H15.
Apply minus_SNo_Le_swap with
x9,
x3,
x4 leaving 4 subgoals.
The subproof is completed by applying H9.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H16.
Apply minus_SNo_Le_swap with
x10,
x4,
x5 leaving 4 subgoals.
The subproof is completed by applying H10.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H17.
Apply minus_SNo_Le_swap with
x11,
x5,
x0 leaving 4 subgoals.
The subproof is completed by applying H11.
The subproof is completed by applying H5.
The subproof is completed by applying H0.
The subproof is completed by applying H18.