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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Assume H0: divides_nat x0 x2.
Assume H1: divides_nat x1 x3.
Apply H0 with divides_nat (mul_SNo x0 x1) (mul_SNo x2 x3).
Assume H2: and (x0omega) (x2omega).
Apply H2 with (∃ x4 . and (x4omega) (mul_nat x0 x4 = x2))divides_nat (mul_SNo x0 x1) (mul_SNo x2 x3).
Assume H3: x0omega.
Assume H4: x2omega.
Assume H5: ∃ x4 . and (x4omega) (mul_nat x0 x4 = x2).
Apply H5 with divides_nat (mul_SNo x0 x1) (mul_SNo x2 x3).
Let x4 of type ι be given.
Assume H6: (λ x5 . and (x5omega) (mul_nat x0 x5 = x2)) x4.
Apply H6 with divides_nat (mul_SNo x0 x1) (mul_SNo x2 x3).
Assume H7: x4omega.
Assume H8: mul_nat x0 x4 = x2.
Apply H1 with divides_nat (mul_SNo x0 x1) (mul_SNo x2 x3).
Assume H9: and (x1omega) (x3omega).
Apply H9 with (∃ x5 . and (x5omega) (mul_nat x1 x5 = x3))divides_nat (mul_SNo x0 x1) (mul_SNo x2 x3).
Assume H10: x1omega.
Assume H11: x3omega.
Assume H12: ∃ x5 . and (x5omega) (mul_nat x1 x5 = x3).
Apply H12 with divides_nat (mul_SNo x0 x1) (mul_SNo x2 x3).
Let x5 of type ι be given.
Assume H13: (λ x6 . and (x6omega) (mul_nat x1 x6 = x3)) x5.
Apply H13 with divides_nat (mul_SNo x0 x1) (mul_SNo x2 x3).
Assume H14: x5omega.
Assume H15: mul_nat x1 x5 = x3.
Apply and3I with mul_SNo x0 x1omega, mul_SNo x2 x3omega, ∃ x6 . and (x6omega) (mul_nat (mul_SNo x0 x1) x6 = mul_SNo x2 x3) leaving 3 subgoals.
Apply mul_SNo_In_omega with x0, x1 leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H10.
Apply mul_SNo_In_omega with x2, x3 leaving 2 subgoals.
The subproof is completed by applying H4.
The subproof is completed by applying H11.
Let x6 of type ο be given.
Assume H16: ∀ x7 . and (x7omega) (mul_nat (mul_SNo x0 x1) x7 = mul_SNo x2 x3)x6.
Apply H16 with mul_SNo x4 x5.
Apply andI with mul_SNo x4 x5omega, mul_nat (mul_SNo x0 x1) (mul_SNo x4 x5) = mul_SNo x2 x3 leaving 2 subgoals.
Apply mul_SNo_In_omega with x4, x5 leaving 2 subgoals.
The subproof is completed by applying H7.
The subproof is completed by applying H14.
Apply mul_nat_mul_SNo with mul_SNo x0 x1, mul_SNo x4 x5, λ x7 x8 . x8 = mul_SNo x2 x3 leaving 3 subgoals.
Apply mul_SNo_In_omega with x0, x1 leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H10.
Apply mul_SNo_In_omega with x4, x5 leaving 2 subgoals.
The subproof is completed by applying H7.
The subproof is completed by applying H14.
Apply mul_SNo_com_4_inner_mid with x0, x1, x4, x5, λ x7 x8 . x8 = mul_SNo x2 x3 leaving 5 subgoals.
Apply nat_p_SNo with x0.
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