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Proofgold Proof

pf
Let x0 of type ι(ιιι) → (ιι) → ιιι be given.
Let x1 of type ι be given.
Let x2 of type ιιι be given.
Let x3 of type ιι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Assume H0: ∀ x6 : ι → ι → ι . (∀ x7 . x7x1∀ x8 . x8x1x2 x7 x8 = x6 x7 x8)∀ x7 : ι → ι . (∀ x8 . x8x1x3 x8 = x7 x8)x0 x1 x6 x7 x4 x5 = x0 x1 x2 x3 x4 x5.
Apply pack_b_u_e_e_0_eq2 with x1, x2, x3, x4, x5, λ x6 x7 . x0 x6 (decode_b (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 1)) (ap (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 2)) (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 3) (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 4) = x0 x1 x2 x3 x4 x5.
Apply pack_b_u_e_e_3_eq2 with x1, x2, x3, x4, x5, λ x6 x7 . x0 x1 (decode_b (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 1)) (ap (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 2)) x6 (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 4) = x0 x1 x2 x3 x4 x5.
Apply pack_b_u_e_e_4_eq2 with x1, x2, x3, x4, x5, λ x6 x7 . x0 x1 (decode_b (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 1)) (ap (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 2)) x4 x6 = x0 x1 x2 x3 x4 x5.
Apply H0 with decode_b (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 1), ap (ap (pack_b_u_e_e x1 x2 x3 x4 x5) 2) leaving 2 subgoals.
The subproof is completed by applying pack_b_u_e_e_1_eq2 with x1, x2, x3, x4, x5.
The subproof is completed by applying pack_b_u_e_e_2_eq2 with x1, x2, x3, x4, x5.