Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Apply unknownprop_82d8b16cbabe15f33566315da037f391b292861be9631cc7d9815c42bac38696 with
x0,
x2,
x1,
add_SNo x4 x6 leaving 5 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H0.
Apply int_add_SNo with
x4,
x6 leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
Apply unknownprop_61887ed89638f3e8ae2bf6a2c384a905c1377bda9906e7801b339098548e1a07 with
x0,
x1,
add_SNo x3 x5,
add_SNo x4 x6 leaving 5 subgoals.
The subproof is completed by applying H0.
Apply int_add_SNo with
x3,
x5 leaving 2 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H4.
Apply int_add_SNo with
x4,
x6 leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H5.
Apply minus_add_SNo_distr with
x4,
x6,
λ x7 x8 . divides_int x0 (add_SNo (add_SNo x3 x5) x8) leaving 3 subgoals.
Apply int_SNo with
x4.
The subproof is completed by applying H3.
Apply int_SNo with
x6.
The subproof is completed by applying H5.
Apply add_SNo_com_4_inner_mid with
x3,
x5,
minus_SNo x4,
minus_SNo x6,
λ x7 x8 . divides_int x0 x8 leaving 5 subgoals.
Apply int_SNo with
x3.
The subproof is completed by applying H2.
Apply int_SNo with
x5.
The subproof is completed by applying H4.
Apply SNo_minus_SNo with
x4.
Apply int_SNo with
x4.
The subproof is completed by applying H3.
Apply SNo_minus_SNo with
x6.
Apply int_SNo with
x6.
The subproof is completed by applying H5.
Apply divides_int_add_SNo with
x0,
add_SNo x3 (minus_SNo x4),
add_SNo x5 (minus_SNo x6) leaving 2 subgoals.
Apply divides_int_diff_SNo_rev with
x0,
x4,
x3 leaving 3 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H2.
The subproof is completed by applying H7.
Apply divides_int_diff_SNo_rev with
x0,
x6,
x5 leaving 3 subgoals.
The subproof is completed by applying H5.
The subproof is completed by applying H4.
The subproof is completed by applying H8.
The subproof is completed by applying H9.