Search for blocks/addresses/...

Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Assume H0: CSNo x0.
Assume H1: CSNo x1.
Assume H2: CSNo x2.
set y3 to be add_CSNo (mul_CSNo x0 x2) (mul_CSNo x1 x2)
Claim L3: ∀ x4 : ι → ο . x4 y3x4 (mul_CSNo (add_CSNo x0 x1) x2)
Let x4 of type ιο be given.
Assume H3: x4 (add_CSNo (mul_CSNo x1 y3) (mul_CSNo x2 y3)).
Apply unknownprop_4be0565ac5b41f138f7a30d0a9f34a5d126bb341d2eeaa545aa7f0c1552b9722 with add_CSNo x1 x2, y3, λ x5 . x4 leaving 3 subgoals.
Apply CSNo_add_CSNo with x1, x2 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
Apply unknownprop_1a3b6d576749bdb66b853eab2e35cc4332be69b97fdfebcc7e17a4a552a3d204 with y3, x1, x2, λ x5 . x4 leaving 4 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
set y5 to be add_CSNo (mul_CSNo x1 y3) (mul_CSNo x2 y3)
Claim L4: ∀ x6 : ι → ο . x6 y5x6 (add_CSNo (mul_CSNo y3 x1) (mul_CSNo y3 x2))
Let x6 of type ιο be given.
Assume H4: x6 (add_CSNo (mul_CSNo x2 x4) (mul_CSNo y3 x4)).
Apply unknownprop_4be0565ac5b41f138f7a30d0a9f34a5d126bb341d2eeaa545aa7f0c1552b9722 with x4, x2, λ x7 x8 . (λ x9 . x6) (add_CSNo x7 (mul_CSNo x4 y3)) (add_CSNo x8 (mul_CSNo x4 y3)) leaving 3 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H0.
Apply unknownprop_4be0565ac5b41f138f7a30d0a9f34a5d126bb341d2eeaa545aa7f0c1552b9722 with x4, y3, λ x7 x8 . (λ x9 . x6) (add_CSNo (mul_CSNo x2 x4) x7) (add_CSNo (mul_CSNo x2 x4) x8) leaving 3 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H1.
The subproof is completed by applying H4.
set y6 to be λ x6 . y5
Apply L4 with λ x7 . y6 x7 y5y6 y5 x7 leaving 2 subgoals.
Assume H5: y6 y5 y5.
The subproof is completed by applying H5.
The subproof is completed by applying L4.
Let x4 of type ιιο be given.
Apply L3 with λ x5 . x4 x5 y3x4 y3 x5.
Assume H4: x4 y3 y3.
The subproof is completed by applying H4.