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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιιι be given.
Assume H0: ∀ x2 . In x2 x0∀ x3 . In x3 x0In (x1 x2 x3) x0.
Let x2 of type ι be given.
Assume H1: In x2 x0.
Let x3 of type ι be given.
Assume H2: In x3 x0.
Let x4 of type ι be given.
Assume H3: In x4 x0.
Let x5 of type ιιι be given.
Assume H4: ∀ x6 . In x6 x0∀ x7 . In x7 x0In (x5 x6 x7) x0.
Let x6 of type ιιιι be given.
Assume H5: ∀ x7 . In x7 x0∀ x8 . In x8 x0∀ x9 . In x9 x0In (x6 x7 x8 x9) x0.
Let x7 of type ιιι be given.
Assume H6: ∀ x8 . In x8 x0∀ x9 . In x9 x0In (x7 x8 x9) x0.
Let x8 of type ι be given.
Assume H7: In x8 x0.
Let x9 of type ιιι be given.
Assume H8: ∀ x10 . In x10 x0∀ x11 . In x11 x0In (x9 x10 x11) x0.
Assume H9: ∀ x10 . In x10 x0(x9 x8 x10 = x10False)False.
Assume H10: ∀ x10 . In x10 x0(x9 x10 x8 = x10False)False.
Assume H11: ∀ x10 . In x10 x0∀ x11 . In x11 x0(x7 x10 (x9 x10 x11) = x11False)False.
Assume H12: ∀ x10 . In x10 x0∀ x11 . In x11 x0(x9 x10 (x7 x10 x11) = x11False)False.
Assume H13: ∀ x10 . In x10 x0∀ x11 . In x11 x0∀ x12 . In x12 x0(x6 x10 x11 x12 = x7 (x9 x11 x10) (x9 x11 (x9 x10 x12))False)False.
Assume H14: ∀ x10 . In x10 x0(x1 x8 x10 = x10False)False.
Assume H15: ∀ x10 . In x10 x0∀ x11 . In x11 x0∀ x12 . In x12 x0(x6 x10 x11 (x5 x10 (x1 x11 (x6 x10 x11 (x5 x10 (x1 x11 (x6 x10 x11 (x5 x10 (x1 x11 (x6 x10 x11 (x5 x10 (x1 x11 (x6 x10 x11 (x5 x10 (x1 x11 x12)))))))))))))) = x12False)False.
Assume H16: ∀ x10 . ...∀ x11 . ...∀ x12 . ...(x6 x10 x11 (x5 x10 (x1 x11 ...)) = ...False)False.
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