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Proofgold Proof

pf
Claim L0: ∀ x0 . ∀ x1 x2 : ι → ι . (∀ x3 . x3x0x1 x3 = x2 x3)binunion (Sing 0) {x1 x3|x3 ∈ x0} = binunion (Sing 0) {x2 x3|x3 ∈ x0}
Let x0 of type ι be given.
Let x1 of type ιι be given.
Let x2 of type ιι be given.
Assume H0: ∀ x3 . x3x0x1 x3 = x2 x3.
Claim L1: {x1 x3|x3 ∈ x0} = {x2 x3|x3 ∈ x0}
Apply ReplEq_ext with x0, x1, x2.
The subproof is completed by applying H0.
Apply L1 with λ x3 x4 . binunion (Sing 0) x4 = binunion (Sing 0) {x2 x5|x5 ∈ x0}.
Let x3 of type ιιο be given.
Assume H2: x3 (binunion (Sing 0) {x2 x4|x4 ∈ x0}) (binunion (Sing 0) {x2 x4|x4 ∈ x0}).
The subproof is completed by applying H2.
Apply In_rec_i_eq with λ x0 . λ x1 : ι → ι . binunion (Sing 0) {x1 x2|x2 ∈ x0}.
The subproof is completed by applying L0.