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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type ιιι be given.
Assume H0: ∀ x2 x3 . x0 x2x0 x3x0 (x1 x2 x3).
Assume H1: ∀ x2 x3 x4 . x0 x2x0 x3x0 x4x1 x2 (x1 x3 x4) = x1 x3 (x1 x2 x4).
Assume H2: ∀ x2 x3 . x0 x2x0 x3x1 x2 x3 = x1 x3 x2.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Assume H3: x0 x2.
Assume H4: x0 x3.
Assume H5: x0 x4.
Assume H6: x0 x5.
Assume H7: x0 x6.
Assume H8: x0 x7.
Assume H9: x0 x8.
Assume H10: x0 x9.
Apply H1 with x7, x8, x9, λ x10 x11 . x1 x2 (x1 x3 (x1 x4 (x1 x5 (x1 x6 x11)))) = x1 x6 (x1 x5 (x1 x4 (x1 x3 (x1 x2 (x1 x9 (x1 x8 x7)))))) leaving 4 subgoals.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
Apply H2 with x7, x9, λ x10 x11 . x1 x2 (x1 x3 (x1 x4 (x1 x5 (x1 x6 (x1 x8 x11))))) = x1 x6 (x1 x5 (x1 x4 (x1 x3 (x1 x2 (x1 x9 (x1 x8 x7)))))) leaving 3 subgoals.
The subproof is completed by applying H8.
The subproof is completed by applying H10.
Let x10 of type ιιο be given.
Apply unknownprop_ab6f1a47a3ec1f8d80a83c2212851d70fcc98f6094439bd6f923c43ce4827d7e with x0, x1, x6, x5, x4, x3, x2, x9, x8, x7, λ x11 x12 . x10 x12 x11 leaving 10 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H7.
The subproof is completed by applying H6.
The subproof is completed by applying H5.
The subproof is completed by applying H4.
The subproof is completed by applying H3.
The subproof is completed by applying H10.
The subproof is completed by applying H9.
The subproof is completed by applying H8.