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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Assume H0: ordinal x0.
Assume H1: ordinal x1.
Apply ordinal_ordsucc_SNo_eq with x0, λ x2 x3 . add_SNo (minus_SNo x3) (ordsucc x1) = add_SNo (minus_SNo x0) x1 leaving 2 subgoals.
The subproof is completed by applying H0.
Apply ordinal_ordsucc_SNo_eq with x1, λ x2 x3 . add_SNo (minus_SNo (add_SNo 1 x0)) x3 = add_SNo (minus_SNo x0) x1 leaving 2 subgoals.
The subproof is completed by applying H1.
Apply minus_add_SNo_distr with 1, x0, λ x2 x3 . add_SNo x3 (add_SNo 1 x1) = add_SNo (minus_SNo x0) x1 leaving 3 subgoals.
The subproof is completed by applying SNo_1.
Apply ordinal_SNo with x0.
The subproof is completed by applying H0.
Apply add_SNo_com_4_inner_mid with minus_SNo 1, minus_SNo x0, 1, x1, λ x2 x3 . x3 = add_SNo (minus_SNo x0) x1 leaving 5 subgoals.
Apply SNo_minus_SNo with 1.
The subproof is completed by applying SNo_1.
Apply SNo_minus_SNo with x0.
Apply ordinal_SNo with x0.
The subproof is completed by applying H0.
The subproof is completed by applying SNo_1.
Apply ordinal_SNo with x1.
The subproof is completed by applying H1.
Apply add_SNo_minus_SNo_linv with 1, λ x2 x3 . add_SNo x3 (add_SNo (minus_SNo x0) x1) = add_SNo (minus_SNo x0) x1 leaving 2 subgoals.
The subproof is completed by applying SNo_1.
Apply add_SNo_0L with add_SNo (minus_SNo x0) x1.
Apply SNo_add_SNo with minus_SNo x0, x1 leaving 2 subgoals.
Apply SNo_minus_SNo with x0.
Apply ordinal_SNo with x0.
The subproof is completed by applying H0.
Apply ordinal_SNo with x1.
The subproof is completed by applying H1.