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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Apply beta with 10, λ x10 . If_i (x10 = 0) x0 (If_i (x10 = 1) x1 (If_i (x10 = 2) x2 (If_i (x10 = 3) x3 (If_i (x10 = 4) x4 (If_i (x10 = 5) x5 (If_i (x10 = 6) x6 (If_i (x10 = 7) x7 (If_i (x10 = 8) x8 x9)))))))), 4, λ x10 x11 . x11 = x4 leaving 2 subgoals.
The subproof is completed by applying unknownprop_ba23a99d385c96fc20e18f31e2884f35e8c8dc96acf9973b3be03f8c1bfc0b50.
Apply If_i_0 with 4 = 0, x0, If_i (4 = 1) x1 (If_i (4 = 2) x2 (If_i (4 = 3) x3 (If_i (4 = 4) x4 (If_i (4 = 5) x5 (If_i (4 = 6) x6 (If_i (4 = 7) x7 (If_i (4 = 8) x8 x9))))))), λ x10 x11 . x11 = x4 leaving 2 subgoals.
The subproof is completed by applying neq_4_0.
Apply If_i_0 with 4 = 1, x1, If_i (4 = 2) x2 (If_i (4 = 3) x3 (If_i (4 = 4) x4 (If_i (4 = 5) x5 (If_i (4 = 6) x6 (If_i (4 = 7) x7 (If_i (4 = 8) x8 x9)))))), λ x10 x11 . x11 = x4 leaving 2 subgoals.
The subproof is completed by applying neq_4_1.
Apply If_i_0 with 4 = 2, x2, If_i (4 = 3) x3 (If_i (4 = 4) x4 (If_i (4 = 5) x5 (If_i (4 = 6) x6 (If_i (4 = 7) x7 (If_i (4 = 8) x8 x9))))), λ x10 x11 . x11 = x4 leaving 2 subgoals.
The subproof is completed by applying neq_4_2.
Apply If_i_0 with 4 = 3, x3, If_i (4 = 4) x4 (If_i (4 = 5) x5 (If_i (4 = 6) x6 (If_i (4 = 7) x7 (If_i (4 = 8) x8 x9)))), λ x10 x11 . x11 = x4 leaving 2 subgoals.
The subproof is completed by applying neq_4_3.
Apply If_i_1 with 4 = 4, x4, If_i (4 = 5) x5 (If_i (4 = 6) x6 (If_i (4 = 7) x7 (If_i (4 = 8) x8 x9))).
Let x10 of type ιιο be given.
Assume H0: x10 4 4.
The subproof is completed by applying H0.