Search for blocks/addresses/...
Proofgold Proof
pf
Claim L0:
...
...
Claim L1:
...
...
Claim L2:
...
...
Claim L3:
...
...
Apply OSNo_proj0proj1_split with
mul_OSNo
Octonion_i0
Octonion_i3
,
minus_OSNo
Complex_i
leaving 4 subgoals.
The subproof is completed by applying L3.
Apply OSNo_minus_OSNo with
Complex_i
.
The subproof is completed by applying L2.
Apply minus_OSNo_proj0 with
Complex_i
,
λ x0 x1 .
OSNo_proj0
(
mul_OSNo
Octonion_i0
Octonion_i3
)
=
x1
leaving 2 subgoals.
The subproof is completed by applying L2.
Apply OSNo_p0_i with
λ x0 x1 .
OSNo_proj0
(
mul_OSNo
Octonion_i0
Octonion_i3
)
=
minus_HSNo
x1
.
Apply mul_OSNo_proj0 with
Octonion_i0
,
Octonion_i3
,
λ x0 x1 .
x1
=
minus_HSNo
Complex_i
leaving 3 subgoals.
The subproof is completed by applying L1.
The subproof is completed by applying L0.
Apply OSNo_p0_i3 with
λ x0 x1 .
add_HSNo
(
mul_HSNo
(
OSNo_proj0
Octonion_i0
)
x1
)
(
minus_HSNo
(
mul_HSNo
(
conj_HSNo
(
OSNo_proj1
Octonion_i3
)
)
(
OSNo_proj1
Octonion_i0
)
)
)
=
minus_HSNo
Complex_i
.
Apply OSNo_p1_i3 with
λ x0 x1 .
add_HSNo
(
mul_HSNo
(
OSNo_proj0
Octonion_i0
)
0
)
(
minus_HSNo
(
mul_HSNo
(
conj_HSNo
x1
)
(
OSNo_proj1
Octonion_i0
)
)
)
=
minus_HSNo
Complex_i
.
Apply OSNo_p0_i0 with
λ x0 x1 .
add_HSNo
(
mul_HSNo
x1
0
)
(
minus_HSNo
(
mul_HSNo
(
conj_HSNo
(
minus_HSNo
Complex_i
)
)
(
OSNo_proj1
Octonion_i0
)
)
)
=
minus_HSNo
Complex_i
.
Apply OSNo_p1_i0 with
λ x0 x1 .
add_HSNo
(
mul_HSNo
0
0
)
(
minus_HSNo
(
mul_HSNo
(
conj_HSNo
(
minus_HSNo
Complex_i
)
)
x1
)
)
=
minus_HSNo
Complex_i
.
Apply mul_HSNo_0L with
0
,
λ x0 x1 .
add_HSNo
x1
(
minus_HSNo
(
mul_HSNo
(
conj_HSNo
(
minus_HSNo
Complex_i
)
)
1
)
)
=
minus_HSNo
Complex_i
leaving 2 subgoals.
The subproof is completed by applying HSNo_0.
Apply conj_minus_HSNo with
Complex_i
,
λ x0 x1 .
add_HSNo
0
(
minus_HSNo
(
mul_HSNo
x1
1
)
)
=
minus_HSNo
Complex_i
leaving 2 subgoals.
The subproof is completed by applying HSNo_Complex_i.
Apply conj_HSNo_i with
λ x0 x1 .
add_HSNo
0
(
minus_HSNo
(
mul_HSNo
(
minus_HSNo
x1
)
1
)
)
=
minus_HSNo
Complex_i
.
Apply minus_HSNo_invol with
Complex_i
,
λ x0 x1 .
add_HSNo
0
(
minus_HSNo
(
mul_HSNo
x1
1
)
)
=
minus_HSNo
Complex_i
leaving 2 subgoals.
The subproof is completed by applying HSNo_Complex_i.
Apply mul_HSNo_1R with
Complex_i
,
λ x0 x1 .
add_HSNo
0
(
minus_HSNo
x1
)
=
minus_HSNo
Complex_i
leaving 2 subgoals.
The subproof is completed by applying HSNo_Complex_i.
Apply add_HSNo_0L with
minus_HSNo
Complex_i
.
Apply HSNo_minus_HSNo with
Complex_i
.
The subproof is completed by applying HSNo_Complex_i.
Apply minus_OSNo_proj1 with
Complex_i
,
λ x0 x1 .
OSNo_proj1
(
mul_OSNo
Octonion_i0
Octonion_i3
)
=
x1
leaving 2 subgoals.
The subproof is completed by applying L2.
Apply OSNo_p1_i with
λ x0 x1 .
OSNo_proj1
(
mul_OSNo
Octonion_i0
Octonion_i3
)
=
minus_HSNo
x1
.
Apply mul_OSNo_proj1 with
Octonion_i0
,
Octonion_i3
,
λ x0 x1 .
x1
=
minus_HSNo
0
leaving 3 subgoals.
The subproof is completed by applying L1.
The subproof is completed by applying L0.
Apply OSNo_p0_i3 with
λ x0 x1 .
add_HSNo
(
mul_HSNo
(
OSNo_proj1
Octonion_i3
)
(
OSNo_proj0
Octonion_i0
)
)
(
mul_HSNo
(
OSNo_proj1
Octonion_i0
)
(
conj_HSNo
x1
)
)
=
minus_HSNo
0
.
Apply OSNo_p1_i3 with
λ x0 x1 .
add_HSNo
(
mul_HSNo
x1
(
OSNo_proj0
Octonion_i0
)
)
(
mul_HSNo
(
OSNo_proj1
Octonion_i0
)
(
conj_HSNo
0
)
)
=
minus_HSNo
0
.
Apply OSNo_p0_i0 with
λ x0 x1 .
add_HSNo
(
mul_HSNo
(
minus_HSNo
Complex_i
)
x1
)
(
mul_HSNo
(
OSNo_proj1
Octonion_i0
)
(
conj_HSNo
0
)
)
=
minus_HSNo
0
.
Apply OSNo_p1_i0 with
λ x0 x1 .
add_HSNo
(
mul_HSNo
(
minus_HSNo
Complex_i
)
0
)
(
mul_HSNo
x1
(
conj_HSNo
0
)
)
=
minus_HSNo
0
.
Apply conj_HSNo_id_SNo with
0
,
λ x0 x1 .
add_HSNo
(
mul_HSNo
(
minus_HSNo
Complex_i
)
0
)
(
mul_HSNo
1
x1
)
=
minus_HSNo
0
leaving 2 subgoals.
The subproof is completed by applying SNo_0.
Apply mul_HSNo_0R with
1
,
λ x0 x1 .
add_HSNo
(
mul_HSNo
(
minus_HSNo
Complex_i
)
0
)
x1
=
minus_HSNo
0
leaving 2 subgoals.
The subproof is completed by applying HSNo_1.
Apply minus_HSNo_0 with
λ x0 x1 .
add_HSNo
(
mul_HSNo
(
minus_HSNo
Complex_i
)
0
)
0
=
x1
.
Apply mul_HSNo_0R with
minus_HSNo
...
,
...
leaving 2 subgoals.
...
...
■