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Proofgold Proof

pf
Let x0 of type ι(ιιι) → (ιιι) → (ιι) → (ιιο) → ι be given.
Let x1 of type ι be given.
Let x2 of type ιιι be given.
Let x3 of type ιιι be given.
Let x4 of type ιι be given.
Let x5 of type ιιο be given.
Assume H0: ∀ x6 : ι → ι → ι . (∀ x7 . prim1 x7 x1∀ x8 . prim1 x8 x1x2 x7 x8 = x6 x7 x8)∀ x7 : ι → ι → ι . (∀ x8 . prim1 x8 x1∀ x9 . prim1 x9 x1x3 x8 x9 = x7 x8 x9)∀ x8 : ι → ι . (∀ x9 . prim1 x9 x1x4 x9 = x8 x9)∀ x9 : ι → ι → ο . (∀ x10 . prim1 x10 x1∀ x11 . prim1 x11 x1iff (x5 x10 x11) (x9 x10 x11))x0 x1 x6 x7 x8 x9 = x0 x1 x2 x3 x4 x5.
Apply unknownprop_b13c89ec6d6c5802a8ef3ca1b1daa3efe6dea6487d1fe1784c8d7e1c7926ce1a with x1, x2, x3, x4, x5, λ x6 x7 . x0 x6 (e3162.. (f482f.. (b1713.. x1 x2 x3 x4 x5) (4ae4a.. 4a7ef..))) (e3162.. (f482f.. (b1713.. x1 x2 x3 x4 x5) (4ae4a.. (4ae4a.. 4a7ef..)))) (f482f.. (f482f.. (b1713.. x1 x2 x3 x4 x5) (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))))) (2b2e3.. (f482f.. (b1713.. x1 x2 x3 x4 x5) (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))))) = x0 x1 x2 x3 x4 x5.
Apply H0 with e3162.. (f482f.. (b1713.. x1 x2 x3 x4 x5) (4ae4a.. 4a7ef..)), e3162.. (f482f.. (b1713.. x1 x2 x3 x4 x5) (4ae4a.. (4ae4a.. 4a7ef..))), f482f.. (f482f.. (b1713.. x1 x2 x3 x4 x5) (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))), 2b2e3.. (f482f.. (b1713.. x1 x2 x3 x4 x5) (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))))) leaving 4 subgoals.
The subproof is completed by applying unknownprop_6b836e8861743f5273e26908db8398c50bb9a4cc55b329c3ce9b1c64d354155b with x1, x2, x3, x4, x5.
The subproof is completed by applying unknownprop_2d22d2ea3328bddbc05fa20bd454c9c6cf8ca53823a7ff88f2e2debf0510cdfd with x1, x2, x3, x4, x5.
The subproof is completed by applying unknownprop_0a08efdef205751a73aef748e9cd0f5472bd08911528d0539b19592a1d4207b7 with x1, x2, x3, x4, x5.
Let x6 of type ι be given.
Assume H1: prim1 x6 x1.
Let x7 of type ι be given.
Assume H2: prim1 x7 x1.
Apply unknownprop_eda749e193ae6abb1c69532f6899877601ce28055c6e5299f2d1815c32b119f0 with x1, x2, x3, x4, x5, x6, x7, λ x8 x9 : ο . iff (x5 x6 x7) x8 leaving 3 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying iff_refl with x5 x6 x7.