Search for blocks/addresses/...

Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιιο be given.
Assume H0: ∀ x2 x3 . x1 x2 x3x1 x3 x2.
Assume H1: ∀ x2 . x2x0atleastp u3 x2not (∀ x3 . x3x2∀ x4 . x4x2(x3 = x4∀ x5 : ο . x5)x1 x3 x4).
Assume H2: ∀ x2 . x2x0atleastp u6 x2not (∀ x3 . x3x2∀ x4 . x4x2(x3 = x4∀ x5 : ο . x5)not (x1 x3 x4)).
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Let x10 of type ι be given.
Let x11 of type ι be given.
Assume H3: x9x0.
Assume H4: x11x0.
Assume H5: x8 = setminus (DirGraphOutNeighbors x0 x1 x4) (Sing x5).
Assume H6: x10 = setminus (DirGraphOutNeighbors x0 x1 x5) (Sing x4).
Assume H7: x9 = {x12 ∈ setminus x0 (binunion (DirGraphOutNeighbors x0 x1 x4) (Sing x4))|equip (binintersect (DirGraphOutNeighbors x0 x1 x12) (DirGraphOutNeighbors x0 x1 x4)) x2}.
Assume H8: x11 = setminus {x12 ∈ setminus x0 (binunion (DirGraphOutNeighbors x0 x1 x4) (Sing x4))|equip (binintersect (DirGraphOutNeighbors x0 x1 x12) (DirGraphOutNeighbors x0 x1 x4)) x3} x10.
Assume H9: ∀ x12 . x12x9nIn x12 x8.
Assume H10: ∀ x12 . x12x9nIn x12 x11.
Assume H11: ∀ x12 . x12x8nIn x12 x11.
Assume H12: x6x9.
Assume H13: x7x11.
Assume H14: x1 x6 x7.
Let x12 of type ιι be given.
Let x13 of type ιι be given.
Assume H15: x1 x6 (x12 x6).
Assume H16: ∀ x14 . x14x8x13 x14{x15 ∈ setminus x0 (binunion (DirGraphOutNeighbors x0 x1 x4) (Sing x4))|equip (binintersect (DirGraphOutNeighbors x0 x1 x15) (DirGraphOutNeighbors x0 x1 x4)) x2}.
Assume H17: ∀ x14 . x14x8x12 (x13 x14) = x14.
Apply unknownprop_b452704b69c2690d64de292592f2c296c8b3728aed73fd19657b521cd4c80c64 with x0, x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13 leaving 17 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
The subproof is completed by applying H11.
The subproof is completed by applying H12.
The subproof is completed by applying H13.
The subproof is completed by applying H14.
The subproof is completed by applying H15.
The subproof is completed by applying H16.
The subproof is completed by applying H17.