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Proofgold Proof

pf
Let x0 of type ι be given.
Assume H0: x0omega.
Assume H1: infinite x0.
Let x1 of type ι be given.
Assume H2: x1omega.
Apply dneg with ∃ x2 . and (x2x0) (x1x2).
Assume H3: not (∃ x2 . and (x2x0) (x1x2)).
Apply H1.
Apply Subq_finite with ordsucc x1, x0 leaving 2 subgoals.
Apply unknownprop_a27dbe9bdb3250ff525cd2b00221a19841e7e622da131f38fcc1540ba15eb9d8 with ordsucc x1.
Apply nat_ordsucc with x1.
Apply omega_nat_p with x1.
The subproof is completed by applying H2.
Let x2 of type ι be given.
Assume H4: x2x0.
Apply ordinal_trichotomy_or_impred with x1, x2, x2ordsucc x1 leaving 5 subgoals.
Apply nat_p_ordinal with x1.
Apply omega_nat_p with x1.
The subproof is completed by applying H2.
Apply nat_p_ordinal with x2.
Apply omega_nat_p with x2.
Apply H0 with x2.
The subproof is completed by applying H4.
Assume H5: x1x2.
Apply FalseE with x2ordsucc x1.
Apply H3.
Let x3 of type ο be given.
Assume H6: ∀ x4 . and (x4x0) (x1x4)x3.
Apply H6 with x2.
Apply andI with x2x0, x1x2 leaving 2 subgoals.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
Assume H5: x1 = x2.
Apply H5 with λ x3 x4 . x3ordsucc x1.
The subproof is completed by applying ordsuccI2 with x1.
The subproof is completed by applying ordsuccI1 with x1, x2.