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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Assume H0: nat_p x0.
Assume H1: nat_p x1.
Apply nat_ind with λ x2 . add_nat x0 x2 = add_nat x1 x2x0 = x1 leaving 2 subgoals.
Apply add_nat_0R with x0, λ x2 x3 . x3 = add_nat x1 0x0 = x1.
Apply add_nat_0R with x1, λ x2 x3 . x0 = x3x0 = x1.
Assume H2: x0 = x1.
The subproof is completed by applying H2.
Let x2 of type ι be given.
Assume H2: nat_p x2.
Assume H3: add_nat x0 x2 = add_nat x1 x2x0 = x1.
Apply add_nat_SR with x0, x2, λ x3 x4 . x4 = add_nat x1 (ordsucc x2)x0 = x1 leaving 2 subgoals.
The subproof is completed by applying H2.
Apply add_nat_SR with x1, x2, λ x3 x4 . ordsucc (add_nat x0 x2) = x4x0 = x1 leaving 2 subgoals.
The subproof is completed by applying H2.
Assume H4: ordsucc (add_nat x0 x2) = ordsucc (add_nat x1 x2).
Apply H3.
Apply ordsucc_inj with add_nat x0 x2, add_nat x1 x2.
The subproof is completed by applying H4.