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Proofgold Proof

pf
Let x0 of type ι be given.
Assume H0: SNo x0.
Assume H1: SNoLt 0 x0.
Let x1 of type ιι be given.
Assume H2: ∀ x2 . x2SNoS_ (SNoLev x0)SNoLt 0 x2and (SNo (x1 x2)) (mul_SNo x2 (x1 x2) = 1).
Apply and3I with ∀ x2 . x2famunion omega (λ x3 . ap (SNo_recipaux x0 x1 x3) 0)SNo x2, ∀ x2 . x2famunion omega (λ x3 . ap (SNo_recipaux x0 x1 x3) 1)SNo x2, ∀ x2 . x2famunion omega (λ x3 . ap (SNo_recipaux x0 x1 x3) 0)∀ x3 . x3famunion omega (λ x4 . ap (SNo_recipaux x0 x1 x4) 1)SNoLt x2 x3 leaving 3 subgoals.
Let x2 of type ι be given.
Assume H3: x2famunion omega (λ x3 . ap (SNo_recipaux x0 x1 x3) 0).
Apply famunionE_impred with omega, λ x3 . ap (SNo_recipaux x0 x1 x3) 0, x2, SNo x2 leaving 2 subgoals.
The subproof is completed by applying H3.
Let x3 of type ι be given.
Assume H4: x3omega.
Assume H5: x2ap (SNo_recipaux x0 x1 x3) 0.
Apply SNo_recipaux_lem1 with x0, x1, x3, SNo x2 leaving 5 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
Apply omega_nat_p with x3.
The subproof is completed by applying H4.
Assume H6: ∀ x4 . x4ap (SNo_recipaux x0 x1 x3) 0and (SNo x4) (SNoLt (mul_SNo x0 x4) 1).
Assume H7: ∀ x4 . x4ap (SNo_recipaux x0 x1 x3) 1and (SNo x4) (SNoLt 1 (mul_SNo x0 x4)).
Apply H6 with x2, SNo x2 leaving 2 subgoals.
The subproof is completed by applying H5.
Assume H8: SNo x2.
Assume H9: SNoLt (mul_SNo x0 x2) 1.
The subproof is completed by applying H8.
Let x2 of type ι be given.
Assume H3: x2famunion omega (λ x3 . ap (SNo_recipaux x0 x1 x3) 1).
Apply famunionE_impred with omega, λ x3 . ap (SNo_recipaux x0 x1 x3) 1, x2, SNo x2 leaving 2 subgoals.
The subproof is completed by applying H3.
Let x3 of type ι be given.
Assume H4: x3omega.
Assume H5: x2ap (SNo_recipaux x0 x1 x3) 1.
Apply SNo_recipaux_lem1 with x0, x1, x3, SNo x2 leaving 5 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
Apply omega_nat_p with x3.
The subproof is completed by applying H4.
Assume H6: ∀ x4 . x4ap (SNo_recipaux x0 x1 x3) 0and (SNo x4) (SNoLt (mul_SNo x0 x4) 1).
Assume H7: ∀ x4 . x4ap (SNo_recipaux x0 x1 x3) 1and (SNo x4) (SNoLt 1 (mul_SNo x0 x4)).
Apply H7 with x2, SNo x2 leaving 2 subgoals.
The subproof is completed by applying H5.
Assume H8: SNo x2.
Assume H9: SNoLt 1 (mul_SNo x0 ...).
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