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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιι be given.
Let x2 of type ι be given.
Assume H0: d7681.. (8eacd.. x0 x1 x2).
Apply H0 with λ x3 . x3 = 8eacd.. x0 x1 x2∀ x4 . prim1 x4 x0prim1 (x1 x4) x0 leaving 2 subgoals.
Let x3 of type ι be given.
Let x4 of type ιι be given.
Assume H1: ∀ x5 . prim1 x5 x3prim1 (x4 x5) x3.
Let x5 of type ι be given.
Assume H2: prim1 x5 x3.
Assume H3: 8eacd.. x3 x4 x5 = 8eacd.. x0 x1 x2.
Apply unknownprop_98aa881f9d512466d5d34d1715cd6bef507b937a21868becb15373f2e71762e4 with x3, x0, x4, x1, x5, x2, ∀ x6 . prim1 x6 x0prim1 (x1 x6) x0 leaving 2 subgoals.
The subproof is completed by applying H3.
Assume H4: and (x3 = x0) (∀ x6 . prim1 x6 x3x4 x6 = x1 x6).
Apply H4 with x5 = x2∀ x6 . prim1 x6 x0prim1 (x1 x6) x0.
Assume H5: x3 = x0.
Assume H6: ∀ x6 . prim1 x6 x3x4 x6 = x1 x6.
Assume H7: x5 = x2.
Apply H5 with λ x6 x7 . ∀ x8 . prim1 x8 x6prim1 (x1 x8) x6.
Let x6 of type ι be given.
Assume H8: prim1 x6 x3.
Apply H6 with x6, λ x7 x8 . prim1 x7 x3 leaving 2 subgoals.
The subproof is completed by applying H8.
Apply H1 with x6.
The subproof is completed by applying H8.
Let x3 of type ιιο be given.
Assume H1: x3 (8eacd.. x0 x1 x2) (8eacd.. x0 x1 x2).
The subproof is completed by applying H1.