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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιο be given.
Let x2 of type ι be given.
Apply unknownprop_cd9802cfa8b6e6a33231f7ea81630a8af696519ed87942920eb067471609b68b with λ x3 x4 : ι → (ι → ο) → ι . In x2 (x4 x0 (λ x5 . x1 x5))and (In x2 x0) (x1 x2).
Apply unknownprop_b257b354d80b58d9a8444b167a21f47b4aabc910dc3698404491d5ef01e18cf3 with ∃ x3 . and (In x3 x0) (x1 x3), In x2 (If_i (∃ x3 . and (In x3 x0) (x1 x3)) (Repl x0 (λ x3 . (λ x4 . If_i (x1 x4) x4 (Eps_i (λ x5 . and (In x5 x0) (x1 x5)))) x3)) 0)and (In x2 x0) (x1 x2) leaving 2 subgoals.
Assume H0: ∃ x3 . and (In x3 x0) (x1 x3).
Claim L1: If_i (∃ x3 . and (In x3 x0) (x1 x3)) (Repl x0 (λ x3 . (λ x4 . If_i (x1 x4) x4 (Eps_i (λ x5 . and (In x5 x0) (x1 x5)))) x3)) 0 = Repl x0 (λ x3 . (λ x4 . If_i (x1 ...) ... ...) ...)
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Apply L1 with λ x3 x4 . In x2 x4and (In x2 x0) (x1 x2).
Assume H2: In x2 (Repl x0 (λ x3 . (λ x4 . If_i (x1 x4) x4 (Eps_i (λ x5 . and (In x5 x0) (x1 x5)))) x3)).
Apply unknownprop_89e422bb3b8a01dd209d7f2f210df650a435fc3e6005e0f59c57a5e7a59a6d0e with x0, λ x3 . If_i (x1 x3) x3 (Eps_i (λ x4 . and (In x4 x0) (x1 x4))), x2, and (In x2 x0) (x1 x2) leaving 2 subgoals.
The subproof is completed by applying H2.
Let x3 of type ι be given.
Assume H3: In x3 x0.
Assume H4: x2 = (λ x4 . If_i (x1 x4) x4 (Eps_i (λ x5 . and (In x5 x0) (x1 x5)))) x3.
Apply unknownprop_b257b354d80b58d9a8444b167a21f47b4aabc910dc3698404491d5ef01e18cf3 with x1 x3, and (In x2 x0) (x1 x2) leaving 2 subgoals.
Assume H5: x1 x3.
Claim L6: x2 = x3
Apply unknownprop_6f44febdf8a865ee94133af873e3c2941a931de6ac80968301360290e02ca608 with x1 x3, x3, Eps_i (λ x4 . and (In x4 x0) (x1 x4)), λ x4 x5 . x2 = x4 leaving 2 subgoals.
The subproof is completed by applying H5.
The subproof is completed by applying H4.
Apply L6 with λ x4 x5 . and (In x5 x0) (x1 x5).
Apply unknownprop_389e2fb1855352fcc964ea44fe6723d7a1c2d512f04685300e3e97621725b977 with In x3 x0, x1 x3 leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H5.
Assume H5: not (x1 x3).
Claim L6: x2 = Eps_i (λ x4 . and (In x4 x0) (x1 x4))
Apply unknownprop_5a150bd86f4285de5d98c60b17d4452a655b4d88de0a02247259cdad6e6d992c with x1 x3, x3, Eps_i (λ x4 . and (In x4 x0) (x1 x4)), λ x4 x5 . x2 = x4 leaving 2 subgoals.
The subproof is completed by applying H5.
The subproof is completed by applying H4.
Apply L6 with λ x4 x5 . and (In x5 x0) (x1 x5).
Apply Eps_i_ex with λ x4 . and (In x4 x0) (x1 x4).
The subproof is completed by applying H0.
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