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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Assume H0: x2UPair x0 x1.
Assume H1: If_i (x00) x0 x1{If_i (x0x3) x0 x1|x3 ∈ prim4 (prim4 x0)}.
Apply UPairE with x2, x0, x1, x2{If_i (x0x3) x0 x1|x3 ∈ prim4 (prim4 x0)} leaving 3 subgoals.
The subproof is completed by applying H0.
Assume H2: x2 = x0.
Apply H2 with λ x3 x4 . x4{If_i (x0x5) x0 x1|x5 ∈ prim4 (prim4 x0)}.
Apply If_i_1 with x0prim4 x0, x0, x1, λ x3 x4 . x3{If_i (x0x5) x0 x1|x5 ∈ prim4 (prim4 x0)} leaving 2 subgoals.
The subproof is completed by applying Self_In_Power with x0.
Apply ReplI with prim4 (prim4 x0), λ x3 . If_i (x0x3) x0 x1, prim4 x0.
The subproof is completed by applying Self_In_Power with prim4 x0.
Assume H2: x2 = x1.
Apply H2 with λ x3 x4 . x4{If_i (x0x5) x0 x1|x5 ∈ prim4 (prim4 x0)}.
Apply If_i_0 with x00, x0, x1, λ x3 x4 . x3{If_i (x0x5) x0 x1|x5 ∈ prim4 (prim4 x0)} leaving 2 subgoals.
The subproof is completed by applying EmptyE with x0.
Apply ReplI with prim4 (prim4 x0), λ x3 . If_i (x0x3) x0 x1, 0.
The subproof is completed by applying Empty_In_Power with prim4 x0.