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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type ιιι be given.
Assume H0: ∀ x2 x3 . x0 x2x0 x3x0 (x1 x2 x3).
Assume H1: ∀ x2 x3 x4 . x0 x2x0 x3x0 x4x1 x2 (x1 x3 x4) = x1 x3 (x1 x2 x4).
Assume H2: ∀ x2 x3 . x0 x2x0 x3x1 x2 x3 = x1 x3 x2.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Assume H3: x0 x2.
Assume H4: x0 x3.
Assume H5: x0 x4.
Assume H6: x0 x5.
Assume H7: x0 x6.
Assume H8: x0 x7.
Assume H9: x0 x8.
Assume H10: x0 x9.
Apply H1 with x7, x8, x9, λ x10 x11 . x1 x2 (x1 x3 (x1 x4 (x1 x5 (x1 x6 x11)))) = x1 x8 (x1 x2 (x1 x5 (x1 x6 (x1 x3 (x1 x4 (x1 x9 x7)))))) leaving 4 subgoals.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
Apply H2 with x7, x9, λ x10 x11 . x1 x2 (x1 x3 (x1 x4 (x1 x5 (x1 x6 (x1 x8 x11))))) = x1 x8 (x1 x2 (x1 x5 (x1 x6 (x1 x3 (x1 x4 (x1 x9 x7)))))) leaving 3 subgoals.
The subproof is completed by applying H8.
The subproof is completed by applying H10.
Apply unknownprop_e22e2c9777599099a08f9ff2ad030c98f408b9e37a1257b1b06916255d6e718e with x0, x1, x2, x3, x4, x5, x6, x8, x1 x9 x7 leaving 9 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H9.
Apply H0 with x9, x7 leaving 2 subgoals.
The subproof is completed by applying H10.
The subproof is completed by applying H8.