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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type ιιι be given.
Assume H0: ∀ x2 x3 . x0 x2x0 x3x0 (x1 x2 x3).
Assume H1: ∀ x2 x3 x4 . x0 x2x0 x3x0 x4x1 (x1 x2 x3) x4 = x1 x2 (x1 x3 x4).
Assume H2: ∀ x2 x3 . x0 x2x0 x3x1 x2 x3 = x1 x3 x2.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Assume H3: x0 x2.
Assume H4: x0 x3.
Assume H5: x0 x4.
Assume H6: x0 x5.
Apply unknownprop_77b4d4df99acd26da01b3d17a9d3db16e9a142757eeed4d0180646664896d9b9 with x0, x1, x2, x3, x4, x5, λ x6 x7 . x7 = x1 x4 (x1 x5 (x1 x2 x3)) leaving 8 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
Apply unknownprop_77b4d4df99acd26da01b3d17a9d3db16e9a142757eeed4d0180646664896d9b9 with x0, x1, x3, x4, x5, x2, λ x6 x7 . x7 = x1 x4 (x1 x5 (x1 x2 x3)) leaving 8 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H3.
Let x6 of type ιιο be given.
Assume H7: x6 (x1 x4 (x1 x5 (x1 x2 x3))) (x1 x4 (x1 x5 (x1 x2 x3))).
The subproof is completed by applying H7.