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Proofgold Proof

pf
Let x0 of type ι(ιο) → ο be given.
Let x1 of type ι(ιο) → ο be given.
Assume H0: ed32f.. x0 x1.
Let x2 of type ι be given.
Assume H1: ordinal x2.
Assume H2: PNo_lenbdd x2 x0.
Assume H3: PNo_lenbdd x2 x1.
Claim L4: ∃ x3 . and (and (ordinal x3) (∃ x4 : ι → ο . 47618.. x0 x1 x3 x4)) (∀ x4 . prim1 x4 x3not (∃ x5 : ι → ο . 47618.. x0 x1 x4 x5))
Apply least_ordinal_ex with λ x3 . ∃ x4 : ι → ο . 47618.. x0 x1 x3 x4.
Apply unknownprop_13deec40494b47380fd1941c6a625d447cd8171018141d4d3bc740ca96c35ef7 with x0, x1, x2, ∃ x3 . and (ordinal x3) (∃ x4 : ι → ο . 47618.. x0 x1 x3 x4) leaving 5 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
Let x3 of type ι be given.
Assume H4: (λ x4 . and (prim1 x4 (4ae4a.. x2)) (∃ x5 : ι → ο . 47618.. x0 x1 x4 x5)) x3.
Apply H4 with ∃ x4 . and (ordinal x4) (∃ x5 : ι → ο . 47618.. x0 x1 x4 x5).
Assume H5: prim1 x3 ....
...
Apply L4 with ∃ x3 . ∃ x4 : ι → ο . 1a487.. x0 x1 x3 x4.
Let x3 of type ι be given.
Assume H5: (λ x4 . and (and (ordinal x4) (∃ x5 : ι → ο . 47618.. x0 x1 x4 x5)) (∀ x5 . prim1 x5 x4not (∃ x6 : ι → ο . 47618.. x0 x1 x5 x6))) x3.
Apply H5 with ∃ x4 . ∃ x5 : ι → ο . 1a487.. x0 x1 x4 x5.
Assume H6: and (ordinal x3) (∃ x4 : ι → ο . 47618.. x0 x1 x3 x4).
Apply H6 with (∀ x4 . prim1 x4 x3not (∃ x5 : ι → ο . 47618.. x0 x1 x4 x5))∃ x4 . ∃ x5 : ι → ο . 1a487.. x0 x1 x4 x5.
Assume H7: ordinal x3.
Assume H8: ∃ x4 : ι → ο . 47618.. x0 x1 x3 x4.
Assume H9: ∀ x4 . prim1 x4 x3not (∃ x5 : ι → ο . 47618.. x0 x1 x4 x5).
Apply H8 with ∃ x4 . ∃ x5 : ι → ο . 1a487.. x0 x1 x4 x5.
Let x4 of type ιο be given.
Assume H10: 47618.. x0 x1 x3 x4.
Let x5 of type ο be given.
Assume H11: ∀ x6 . (∃ x7 : ι → ο . 1a487.. x0 x1 x6 x7)x5.
Apply H11 with x3.
Let x6 of type ο be given.
Assume H12: ∀ x7 : ι → ο . 1a487.. x0 x1 x3 x7x6.
Apply H12 with x4.
Apply and3I with ordinal x3, 47618.. x0 x1 x3 x4, ∀ x7 . prim1 x7 x3∀ x8 : ι → ο . not (47618.. x0 x1 x7 x8) leaving 3 subgoals.
The subproof is completed by applying H7.
The subproof is completed by applying H10.
Let x7 of type ι be given.
Assume H13: prim1 x7 x3.
Let x8 of type ιο be given.
Assume H14: 47618.. x0 x1 x7 x8.
Apply H9 with x7 leaving 2 subgoals.
The subproof is completed by applying H13.
Let x9 of type ο be given.
Assume H15: ∀ x10 : ι → ο . 47618.. x0 x1 x7 x10x9.
Apply H15 with x8.
The subproof is completed by applying H14.