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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Assume H0: prim1 x3 (0fc90.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))) (λ x4 . If_i (x4 = 4a7ef..) x0 (If_i (x4 = 4ae4a.. 4a7ef..) x1 x2))).
Claim L1: ∃ x4 . and (prim1 x4 (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) (∃ x5 . and (prim1 x5 (If_i (x4 = 4a7ef..) x0 (If_i (x4 = 4ae4a.. 4a7ef..) x1 x2))) (x3 = aae7a.. x4 x5))
Apply unknownprop_d4dc73f3cbfe4c22363272ac418d035b8e77c49433b0870b96bee8fa9c46bfcf with 4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)), λ x4 . If_i (x4 = 4a7ef..) x0 (If_i (x4 = 4ae4a.. 4a7ef..) x1 x2), x3.
The subproof is completed by applying H0.
Apply exandE_i with λ x4 . prim1 x4 (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))), λ x4 . ∃ x5 . and (prim1 x5 (If_i (x4 = 4a7ef..) x0 (If_i (x4 = 4ae4a.. 4a7ef..) x1 x2))) (x3 = aae7a.. x4 x5), ∃ x4 . and (prim1 x4 (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) (∃ x5 . x3 = aae7a.. x4 x5) leaving 2 subgoals.
The subproof is completed by applying L1.
Let x4 of type ι be given.
Assume H2: prim1 x4 (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))).
Assume H3: ∃ x5 . and (prim1 x5 (If_i (x4 = 4a7ef..) x0 (If_i (x4 = 4ae4a.. 4a7ef..) x1 x2))) (x3 = aae7a.. x4 x5).
Apply exandE_i with λ x5 . prim1 x5 (If_i (x4 = 4a7ef..) x0 (If_i (x4 = 4ae4a.. 4a7ef..) x1 x2)), λ x5 . x3 = aae7a.. x4 x5, ∃ x5 . and (prim1 x5 (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) (∃ x6 . x3 = aae7a.. x5 x6) leaving 2 subgoals.
The subproof is completed by applying H3.
Let x5 of type ι be given.
Assume H4: prim1 x5 (If_i (x4 = 4a7ef..) x0 (If_i (x4 = 4ae4a.. 4a7ef..) x1 x2)).
Assume H5: x3 = aae7a.. x4 x5.
Let x6 of type ο be given.
Assume H6: ∀ x7 . and (prim1 x7 (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) (∃ x8 . x3 = aae7a.. x7 x8)x6.
Apply H6 with x4.
Apply andI with prim1 x4 (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))), ∃ x7 . x3 = aae7a.. x4 x7 leaving 2 subgoals.
The subproof is completed by applying H2.
Let x7 of type ο be given.
Assume H7: ∀ x8 . x3 = aae7a.. x4 x8x7.
Apply H7 with x5.
The subproof is completed by applying H5.