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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Apply set_ext with binintersect x0 (binintersect x1 x2), binintersect (binintersect x0 x1) x2 leaving 2 subgoals.
Apply binintersect_Subq_max with binintersect x0 x1, x2, binintersect x0 (binintersect x1 x2) leaving 2 subgoals.
Apply binintersect_Subq_max with x0, x1, binintersect x0 (binintersect x1 x2) leaving 2 subgoals.
The subproof is completed by applying binintersect_Subq_1 with x0, binintersect x1 x2.
Apply Subq_tra with binintersect x0 (binintersect x1 x2), binintersect x1 x2, x1 leaving 2 subgoals.
The subproof is completed by applying binintersect_Subq_2 with x0, binintersect x1 x2.
The subproof is completed by applying binintersect_Subq_1 with x1, x2.
Apply Subq_tra with binintersect x0 (binintersect x1 x2), binintersect x1 x2, x2 leaving 2 subgoals.
The subproof is completed by applying binintersect_Subq_2 with x0, binintersect x1 x2.
The subproof is completed by applying binintersect_Subq_2 with x1, x2.
Apply binintersect_Subq_max with x0, binintersect x1 x2, binintersect (binintersect x0 x1) x2 leaving 2 subgoals.
Apply Subq_tra with binintersect (binintersect x0 x1) x2, binintersect x0 x1, x0 leaving 2 subgoals.
The subproof is completed by applying binintersect_Subq_1 with binintersect x0 x1, x2.
The subproof is completed by applying binintersect_Subq_1 with x0, x1.
Apply binintersect_Subq_max with x1, x2, binintersect (binintersect x0 x1) x2 leaving 2 subgoals.
Apply Subq_tra with binintersect (binintersect x0 x1) x2, binintersect x0 x1, x1 leaving 2 subgoals.
The subproof is completed by applying binintersect_Subq_1 with binintersect x0 x1, x2.
The subproof is completed by applying binintersect_Subq_2 with x0, x1.
The subproof is completed by applying binintersect_Subq_2 with binintersect x0 x1, x2.