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Proofgold Proof

pf
Assume H0: ∀ x0 x1 . ordinal x0ordinal (ordsucc x1)or (ordsucc x1x0) (x0 = ordsucc x1).
Claim L1: or (10) (0 = 1)
Apply H0 with 0, 0 leaving 2 subgoals.
The subproof is completed by applying ordinal_Empty.
Apply ordinal_ordsucc with 0.
The subproof is completed by applying ordinal_Empty.
Claim L2: 10False
Assume H2: 10.
Apply EmptyE with 1.
The subproof is completed by applying H2.
Claim L3: 0 = 1False
The subproof is completed by applying neq_0_ordsucc with 0.
Apply unknownprop_f2665e7d9d9aff04a54f0326c3182ba0030a187604c1d0b27e5a9bebd4051089 with 10, 0 = 1, False leaving 3 subgoals.
The subproof is completed by applying L1.
The subproof is completed by applying L2.
The subproof is completed by applying L3.